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3 years ago

What is the slope of 0, 3 and 0, -5

Mathematics

2 answers:

max2010maxim [7]3 years ago

6 0

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (0,) and (0, -5). Substitute:

$m=\dfrac{-5-3}{0-0}=\dfrac{-8}{0}\ \ \ \bbbig{!!!!!}\ \text{division by 0 !!!!!}$

<h3>Answer: slope is undefined</h3>

This is the line lying on the y-axis (vertical line x = 0).

Rainbow [258]3 years ago

3 0

Answer:

slope is undefined

Step-by-step explanation:

Calculate the slope m using the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (0, - 5)

m = $\frac{-5-3}{0-0}$ = $\frac{-8}{0}$

Division by 0 is undefined, hence slope is undefined

In fact this is the slope of a vertical line

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A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues,

EleoNora [17]

Answer:

7,692 moose.

Explanation:

The table that shows the pattern for this question is:

Time (year) Population

0 40

1 62

2 96

3 149

4 231

A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.

Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.

Thus you must find both P₀ and r.

1) P₀ 

Using the first term of the sequence (0, 40) you get:

P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀

Then, P₀ = 40

2) r

Take two consecutive terms of the sequence:

P(0) = 40 r⁰ = 40

P(1) = 40 r¹ = 40r = 62

P(1) / P(0) = 40r / 40 = 62/40

r = 62/40 = 1.55

You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55

3) Model

Thus, your model is P(x) = 40(1.55)ˣ

 4) Population of moose after 12 years

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3 years ago

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3 years ago

A stadium has 50,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. The number of seats in Sect

Pepsi [2]

Answer:

Section A holds 25,000 seats, section B holds 14,500 seats and section C holds 10,500 seats.

Step-by-step explanation:

From the information given you can write the following equations:

A+B+C=50,000 (1)

28A+24B+20C=1,258,000 (2)

A=B+C (3)

A= number of seats in section A

B= number of seats in section B

C= number of seats in section C

You can replace (3) in (1) and (2) to get two equations:

B+C+B+C=50,000

2B+2C=50000

28(B+C)+24B+20C=1,258,000

28B+24B+28C+20C=1,258,000

52B+48C=1,258,000

The two equations are:

2B+2C=50000 (4)

52B+48C=1,258,000 (5)

You can isolate B in (4):

2B=50,000-2C

B=(50,000/2)-(2C/2)

B=25,000-C

Now, you can replace B in (5):

52(25,000-C)+48C=1,258,000

1,300,000-52C+48C=1,258,000

1,300,000-1,258,000=4C

42,000=4C

C=42,000/4

C=10,500

Now, you can replace the value of C in B=25,000-C:

B=25,000-10,500

B=14,500

Finally, you can replace the values of B and C in A=B+C to find A:

A=14,500+10,500

A=25,000

According to this, the answer is that section A holds 25,000 seats, section B holds 14,500 and section C holds 10,500.

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