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pshichka [43]
3 years ago
5

Rewrite the quadratic function in vertex form. Y=5x^2-10x+2

Mathematics
1 answer:
Natalka [10]3 years ago
3 0

Answer:

y = 5x2 + 10x - 15

We want this in format y = a(x-h)2 + k

where the vertex will be at (h,k)

y = 5(x2+2x) - 15

Complete the square on x2+2x

y = 5(x2+2x+1) - 15 - 5

We subtract 5 at the end because we are actually adding 5(1) = 5

so we need to remove it also to keep the total equal

y = 5(x+1)2 - 20

The vertex is at (-1,-20)

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