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3 years ago

What is 5(4x-5y)-2=453

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

5(4x-5y)-2=453

5(4x-5y)=455

4x-5y=91

When solving for x

4x=5y+91

x= 5y+91/4

When solving for y

-5y=-4x+91

y=-4x+91/-5

<em>i hope im right...</em>

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2 years ago

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Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

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$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

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in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

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3 years ago