Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test
Formula : 
Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
List this from least to greatest:.5, 3/16, .75, 5.48
3/16 = 0.1875
so from least to greatest
3/16, .5, .75, 5.48
Step-by-step explanation:
< AEB + < BEC = 180° {BEING LINEAR PAIR }
26° + < BEC = 180°
< BEC = 180° - 26°
< BEC = 154°
ARC BC = < BEC ( relation between arc and central angle)
Arc BC = 154°
Hope it will help :)
The answer is the first one, (2)
Answer:
38.68 degrees
Step-by-step explanation:
In this equation you are trying to find the degrees using the hypotenuse and opposite. So you have to use the function sin^-1(5/8). Because when using Sin it is opposote ove hypotenuse.
