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m_a_m_a [10]
2 years ago
5

You decide to borrow $500 to go on a trip. You go to the bank and borrow the money at 11% for 2 years. Find the interest you wil

l pay on the loan.
Mathematics
2 answers:
Tcecarenko [31]2 years ago
4 0
$500_100%
X$___11%

11 x 500
————— = 55 $
100
juin [17]2 years ago
4 0
It would be 55$ for just one year & for 2 years 55 x 2= 110$
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Find the product of 7xy and x to the 14th z
8090 [49]

Answer:

7x^15yz

Step-by-step explanation:

7(x^14x)y · z

7(x^14+1)y · z

7x^15yz

8 0
3 years ago
Helen is putting a fence around her flower garden, which is in the shape of half of a circle and a rectangle. If the semicircle
erastova [34]

Answer:

Part 1) Helen will need 38 feet of fencing

Part 2) The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) The approximate distance around half of the circle is 11 feet

Step-by-step explanation:

Part 1) How much fencing will Helen need?

Find out the perimeter

we know that

The perimeter of the figure is equal to the sum of three sides of the rectangular section plus the circumference of a semicircle

so

P=2L+W+\frac{1}{2}\pi D

we have

L=10\ ft\\W=7\ ft\\D=7\ ft\\\pi =\frac{22}{7}

substitute

P=2(10)+7+\frac{1}{2}(\frac{22}{7})(7)

P=20)+7+11=38\ ft

therefore

Helen will need 38 feet of fencing

Part 2)  What is the perimeter around the three sides of the rectangular section of the garden?

P=2L+W

we have

L=10\ ft\\W=7\ ft

substitute

P=2(10)+7

P=20+7=27\ ft

therefore

The perimeter around the three sides of the rectangular section of the garden is 27 feet

Part 3) What is the approximate distance around half of the circle?

Find the circumference of semicircle

C=\frac{1}{2}\pi D

we have

D=7\ ft\\\pi =\frac{22}{7}

substitute

C=\frac{1}{2}(\frac{22}{7})(7)

C=11\ ft

therefore

The approximate distance around half of the circle is 11 feet

4 0
2 years ago
Read 2 more answers
A tree outside Dave’s house is 12 feet tall
Oxana [17]

Answer:

wheres the reszt of the question?

Step-by-step explanation:

4 0
3 years ago
There are 3 types of gummy bears:
mr Goodwill [35]

Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:

12.1/10 = 1.21 grams.

10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:

23.1/10 = 2.31 grams.

1 super bear weights to 2250 grams, hence the proportion between the <u>weight of a super bear and the weight of a mini-bear</u> is:

2250/1.21 = 1860.

The proportion between the <u>weight of a super bear and the weight of a regular bear</u> is:

2250/2.31 = 974.

The difference of proportions is given by:

1860 - 974 = 886.

It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

5 0
9 months ago
Find fg(x) <br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%202" id="TexFormula1" title="f(x
Kipish [7]

Answer:

f(g(x)) = x^4 + 12x^3 + 14x^2 -132x + 123

Step-by-step explanation:

Here, we simply will place g(x) into f(x)

So every x in f(x) is replaced by g(x)

Thus, we have;

(x^2 + 6x + 11)^2 + 2

= (x^2+6x-11)(x^2 + 6x -11) + 2

= x^4 + 6x^3 -11x^2 + 6x^3 + 36x^2 - 66x -11x^2 -66x + 121 + 2

= x^4 + 12x^3 + 14x^2 -132x + 123

7 0
2 years ago
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