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Minchanka [31]
3 years ago
15

What can you infer about the population from each data set represented below? Please help

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

Well around 5-8 miles were jogged daily.

Step-by-step explanation:

Thats all i know

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Factor completely, then place the answer in the proper location on the grid. <br> 6х^2 - 3х - 30
Tems11 [23]

Answer:

3(x + 2)(2x - 5)

Step-by-step explanation:

Given

6x² - 3x - 30 ← factor out 3 from each term

= 3(2x² - x - 10) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 10 = - 20 and sum = - 1

The factors are + 4 and - 5

Use these factors to split the x- term

2x² + 4x - 5x - 10 ( factor the first/second and third/fourth terms )

= 2x(x + 2) - 5(x + 2) ← factor out (x + 2) from each term

= (x + 2)(2x - 5), thus

2x² - x - 10 = (x + 2)(2x - 5) and

6x² - 3x - 30

= 3(x + 2)(2x - 5) ← in factored form

7 0
3 years ago
What's sss, sas, asa, aas, and hi. when it comes to solving triangles?<br>​
tekilochka [14]

Answer:

SSS = side side side

SAS = side angle side

ASA = angle side angle

AAS = angle angle side

8 0
2 years ago
Solve the following system of equations. Write each of your answers as a fraction reduced to lowest terms. In other words, write
morpeh [17]

Answer:

x = 57/28

y = -95/84

z = 97/168

Step-by-step explanation:

Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html

Start with the expanded array:

\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]

then using the tool provided, make row operations until you find the solution:

r2 = r2-3r1

\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]

r3 = r3+2r1

\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]

r2 = r2*(-1/13)

\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]

r1 = r1- r2*5

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]

r3 = r3+ r2*-3

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]

r3 = r3*13/168

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]

r2 = r2- r3*22/13

\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]

r2 = r2+ r3*6/13

\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]

Here you have a reduced array an therefore the answers to each variable are on each row:

\left[\begin{array}{c}x\\y\\z\end{array}\right]

8 0
3 years ago
Using the quadratic formula to solve 7x2 – x = 7, what are the values of x?
Kruka [31]
How the quadratic formula works:

For any quadratic equation ax² + bx + c = 0, the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

In the case of our equation 7x² - x = 7, first we need to subtract 7 from each side so that we have 0 on the right.
7x² - x - 7 = 0

Identify the values of a, b, and c.
a = 7, b = -1, and c = -7.

Plug these into our quadratic formula and solve.

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(7)(-7)}}{2(7)}=\boxed{\frac{1\pm\sqrt{197}}{14}

There are two values for x: (1+√197)/14 and (1-√197)/14.
The approximate values for these are 1.073976 and -0.931119.
5 0
3 years ago
Read 2 more answers
You have 12 CDs and choose 4 of them to play one evening. How many
e-lub [12.9K]

Answer:

3 orders of CDs

Step-by-step explanation:

So if you have 12 CDs and you are choosing 4 for one evening you get 8 more CDs for 3 evening.So what i did is 12 - 4 and it is equal to 8 CDs and  You divide 4 in to 12 and it gives you 3.Your answer is 3 order of CDs because the question is asking how many order of CDs are possible for playing 4 CDs?

4 0
3 years ago
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