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shepuryov [24]
3 years ago
10

Say the funniest thing as an answer lol

Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

“Your mother has been with us for 20 years,” said John. “Isn’t it time she got a place of her own?”

“My mother?” replied Helen. “I thought she was your mother.”

Step-by-step explanation:

They don't know who's mother it is therefore implying that they have been living with a stranger, demonstrating the panic and realization felt by the characters. sorry this is my idea of humour

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Least to greatest 4 1/3, the square root of 43, 12/4, 4.13
kicyunya [14]
<span>Least to greatest
</span><span>12/4, </span>4.13,  4 1/3 , the square root of 43
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Amir has $200 budget to spend on a graduation party for his son he already has purchased $122 worth of drinks and party supplies
Bas_tet [7]

Answer: C, D, and E

Step-by-step explanation:

200-122=78 remaining

A: 7*11.75= 82.25

B: 10*11.75= 117.50

C: 9*6.80=61.20

D: 11*6.80=74.80

E: 70*1.10=77.00

F: 71*1.10=78.10

Only C, D and E are below the dollars remaining in the budget.

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3 years ago
What is the decimal multiplier to increase by 99%? need it now
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Answer:

To work out the multiplier, first add or subtract the percentage from 100, then convert to a decimal. Example: we want to add 20% to £110. To work out the multiplier, add 20 to 100, to get 120, and then change it to a decimal (divide by 100) to get 1.2.

meiabatten191 helped me out on this question too.

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Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea
lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

\int\limits^y_0 {kx^{2} } \, =1

where y=23

Clearing k=0.00025

a) Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5

b)Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2}  =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6

c) The function is equal to:

f(x)=k(1+2x)

\int\limits^y_0 {k(1+2x)} \, =1

where y=20

k=0.0024

Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3

d) Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2}   =198.4-176.89=21.51

8 0
4 years ago
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