First, we'll find the area of the large section, including the smaller section that is white.
Area of a circle: pi x r^2
A = pi x 7^2
A = 49pi x 120/360
A = 49/3 pi cm^2
Now, we'll find the area of the small section.
A = pi x 3^2
A = 9 pi x 120/360
A = 3pi cm^2
All that's left to do now is subtract.
49/3 pi - 3 pi
40/3 pi cm^2
(or 13 1/3 = 13.33 cm^2)
Hope this helps!
Answer: 37 units
Step-by-step explanation:
This also works as the height of the triangle.
This also works as the base of the triangle.
Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.
To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.
![s=\sqrt[]{A}](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7BA%7D)
Let's work with Blue.
![s=\sqrt[]{144units^2} \\s=12units](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7B144units%5E2%7D%20%5C%5Cs%3D12units)
Now Pink.
![s=\sqrt[]{1225units^2}\\s=35units](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7B1225units%5E2%7D%5C%5Cs%3D35units)
So we have a triangle with a base of 35 units and a height of 12 units.
Now let's use the pythagoream's theorem to solve.
![c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2%5C%5Cc%3D%5Csqrt%5B%5D%7Ba%5E2%2Bb%5E2%7D%20%5C%5Cc%3D%5Csqrt%5B%5D%7B%2812units%29%5E2%2B%2835units%29%5E2%7D%5C%5Cc%3D%5Csqrt%5B%5D%7B144units%5E2%2B1225units%5E2%7D%5C%5C%20c%3D%5Csqrt%5B%5D%7B1369units%5E2%7D%5C%5C%20c%3D37units)
Expanded Notation Form:
5,000,000
+ 600,000
+ 70,000
+ 8,000
+ 200
+ 0
+ 9
Expanded Factors Form:
5 × 1,000,000
+ 6 × 100,000
+ 7 × 10,000
+ 8 × 1,000
+ 2 × 100
+ 0 × 10
+ 9 × 1
Expanded Exponential Form:
5 × 106
+ 6 × 105
+ 7 × 104
+ 8 × 103
+ 2 × 102
+ 0 × 101
+ 9 × 100
Answer:
401
Step-by-step explanation:
a=5
d=9-5=4
