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Nataly [62]
3 years ago
5

The hypotenuse of a right

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0
Answer is 13.41

Explanation: If you use the Pythagorean Therom correctly, you would have to do 6 to the power of 2 plus 12 to the power of 2. 6 to the power of 2 is 36 and 12 to the power of 2 is 144, add them both that would get you 180. After that you would have to square root 180, you have to get you calculator and do that. After you do that you will get 13.41. Please mark brainlest answer

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Read 2 more answers
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

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3 years ago
For which of the following compound inequalities is there no solution?
tamaranim1 [39]

Answer:

I THINK A

Step-by-step explanation:

3 0
3 years ago
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