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4 years ago

Find the fourth term of the sequence given by the rule tn=4(2)^n-1

1 answer:

8 0

Answer: Choice A) 32

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Plug n = 4 into the formula

tn = 4(2)^(n-1)
t4 = 4(2)^(4-1) ... every n is replaced with 4
t4 = 4(2)^3
t4 = 4(8)
t4 = 32

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<h2>Given Question, </h2>

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