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Roman55 [17]
3 years ago
13

Find the fourth term of the sequence given by the rule tn=4(2)^n-1

Mathematics
1 answer:
Andre45 [30]3 years ago
8 0
Answer: Choice A) 32

-----------------------------------------------
-----------------------------------------------

Plug n = 4 into the formula

tn = 4(2)^(n-1)
t4 = 4(2)^(4-1) ... every n is replaced with 4
t4 = 4(2)^3
t4 = 4(8)
t4 = 32
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