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3 years ago

7

Find the equation of the ellipse with the following properties.

1 answer:

zalisa [80]3 years ago

6 0

Equation of an ellipse:

(x-h)²/a² + (y-k)²/b² = 1
Since it passes through the origin (0,0) , then h = k = 0 hence the equation:
(x-0)²/a² + (y-0)²/b² = 1
x²/a² + y²/b² = 1

2a = major axis = 2.|5| + |-5| = 10. then a = 5 and a² = 25
2b = minor axis = 2.|3| + |-3| = 6. then b = 3 and b² = 9

Then the final equation is:
x²/25 + y²/9 = 1

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Q(a+1) - 2q(a) if q(x) = x²+3x+4

siniylev [52]

$q(x) = {x}^{2} + 3x + 4$

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

$q(a) = {a}^{2} + 3a + 4$

Multiply sides by -2 :

$- 2q(a) = - 2( {a}^{2} + 3a + 4)$

$- 2q(a) = - 2 {a}^{2} - 6a - 8$

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

$q(a + 1) = ({a + 1})^{2} + 3(a + 1) + 4 \\$

$q(a + 1) = {a}^{2} + 2a + 1 + 3a + 3 + 4 \\$

$q(a + 1) = {a}^{2} + 5a + 8$

_________________________________

Step (3)

$q(a + 1) - 2q(a) =$

${a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 = \\$

$- {a}^{2} - a = - a(a + 1)$

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0

3 years ago

What is the weight of the plane with 81 gallons of fuel in its tanks?

JulijaS [17]

The weight of a plane with 81 gallons of fuel in the tank is about 44 tons

3 0

3 years ago

To solve the equation X - 62 = 123, you would ?

Ratling [72]

X-62=123
+62 +62
_________
x=185
you need to add a positive 62 from each side so -62+62=0 and 123+62=185
therefore, x=185
:Done! hope this helps!

6 0

3 years ago

Pls help!!!!Shawn used 15 centimeters of tape to wrap 5 presents . How much tape will Shawn need I all if he has to wrap 13 pres

Ilia_Sergeevich [38]

Answer:39

Step-by-step explanation:

15÷5=3

3×13=39

3 0

3 years ago

Consider Z1= 4-4 radical 3i and Z2= -16 i. What is Z1-Z2?

goldfiish [28.3K]

Answer:

Option (3)

Step-by-step explanation:

$Z_1=4-4\sqrt{3}i$

$Z_2=-16i$

$Z_1-Z_2=(4-4\sqrt{3}i)-(-16i)$

$=4-4\sqrt{3}i+16i$

$=4-(4\sqrt{3}i-16i)$

$=4-4(\sqrt{3}-4)i$

Therefore, Option (3) will be the correct option.

8 0

2 years ago