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2 years ago

Help my please please

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

4 0

Answer:

Rectangle:6+5=11(Odd)

Triangle:6+6=12(even)

Star:4+3=7(odd)

Pentagon:9+8=17(odd)

Hexagon:6+6+12(even)

Circle:4+4=8(even)

Step-by-step explanation:

Hope this helps:)

LiRa [457]2 years ago

4 0

Answer:

odd, even

odd, odd

even, even

Step-by-step explanation:

Number the pictures starting from left to right and the down, then pictures 1, 3 4 are odd

2, 5, 6 are even.

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Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance

lana66690 [7]

Answer:

Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.

Let p = population proportion of users who develop nausea

So, Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Here, null hypothesis states that 20% of users develop nausea.

And alternate hypothesis states that more than 20% of users develop nausea.

The test statistics that would be used here is One-sample z proportion test statistics.

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of users who develop nausea in a sample of 241 subjects = $\frac{54}{241}$

n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0

3 years ago

Solve for x 2x - 1 - 1 = x - 3 - ( -5 + x )

Nana76 [90]

Answer:

x=2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2x−1−1=x−3−(−5+x)

2x−1−1=x−3+−1(−5+x)(Distribute the Negative Sign)

2x−1−1=x+−3+(−1)(−5)+−1x

2x−1−1=x+−3+5+−x

2x+−1+−1=x+−3+5+−x

(2x)+(−1+−1)=(x+−x)+(−3+5)(Combine Like Terms)

2x+−2=2

2x−2=2

Step 2: Add 2 to both sides.

2x−2+2=2+2

2x=4

Step 3: Divide both sides by 2.

x=2

8 0

2 years ago

"What is the probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice? Assume you’re throwing a single d

dem82 [27]

Answer:

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

Step-by-step explanation:

For each throw, there are only two possible outcomes. Either it is a '3', or it is not. This means that we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

There are 6 possible outcomes for the dice. This means that the probability that it is a '3' is $\frac{1}{6} = 0.167$

There are 10 throws, so $n = 10$ .

Probability of throwing AT LEAST two ‘3’s on the dice?

Either you throw less than two, or you throw at least two. The sum of the probabilities of these events is 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$ .

In which

$P(X < 2) = P(X = 0) + P(X = 1)$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.167)^{0}.(0.833)^{10} = 0.1609$

$P(X = 1) = C_{10,1}.(0.167)^{1}.(0.833)^{9} = 0.3225$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.1609 + 0.3225 = 0.4834$ .

Finally:

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4839 = 0.5161$ .

There is a 51.61% probability that in 10 dice throws, you will throw AT LEAST two ‘3’s on the dice.

5 0

2 years ago

HELP, 66% because of you beauty's! CAN WE GET TO 80, tho? Pwease

Mars2501 [29]

Answer:

49 square miles

Step-by-step explanation:

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GaryK [48]

Answer:

Step-by-step explanation:

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3 years ago

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