Using the z-distribution, it is found that the 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have that:
- 95% confidence level, hence
, z is the value of Z that has a p-value of
, so
.
- 49% out of 2001 U.S. adults play video games, hence
.
The lower bound of the interval is:

The upper bound of the interval is:

The 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.
To learn more about the z-distribution, you can take a look at brainly.com/question/25730047
Answer:
(-2,-3/2)
Step-by-step explanation:
Midpoint formula=(x1+x2/2, y1+y2/2)
So...
(3+-7/2, -5+2/2) =
(-2, -3/2)
Answer:
Subtract 100 then take 10% off
Step-by-step explanation:
=12
u add all the number together and divide by how many numbers there are :)
3/10 of 5/6....." of " means multiply
3/10 * 5/6 = 15/60 reduces to 1/4......1/4 of her garden has red flowers