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Svetradugi [14.3K]
3 years ago
9

There are 17 trees along the road from Basil's home to a swimming pool. On his way way to and from a swim Basil marks some trees

with a red stripe. On his way to the pool he marks the first, the third, the fifth tree and so on. On his way back again, he marks the first tree he comes to, the fourth tree, the seventh tree and so on, missing out two trees each time. By the time he gets home how many trees have no mark?

Mathematics
1 answer:
morpeh [17]3 years ago
4 0

Answer:

Number of trees not marked is 6

Step-by-step explanation:

Base on the scenario been described in the question, we can find the solution in the file attached

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28.
Artyom0805 [142]

Answer:

50

Step-by-step explanation:

30% * n = 15

Change to decimal form

.30 *n = 15

Divide each side by .30

.30n/.30 = 15/.30

n =50

The number is 50

7 0
3 years ago
(-3,20) (3,0) (18,20) (13,18) is it a function
S_A_V [24]

Answer: No

Step-by-step explanation: The table does not have a function rule that is linear, quadratic, or cubic.

4 0
3 years ago
I had a dream of a beautiful cupcake tree, growing 4 loveee cupcakes every 12 hours for 36 hours. Please make my dream come true
weqwewe [10]

Answer: sounds sweet:)

Step-by-step explanation:

7 0
3 years ago
Which of these needs the denominator rationalized? -PLEASE HELP
valentinak56 [21]

Answer:

option b

Step-by-step explanation:

\sqrt{ \frac{5}{3} }

\frac{ \sqrt{5} }{ \sqrt{3} }

the denominator is in the surd form, so it must be rationalized

4 0
3 years ago
Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz
klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

A.

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

B.

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

C.

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0
3 years ago
Read 2 more answers
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