Answer:
D) t=4d+5
Step-by-step explanation:
If d=1,
If d=2,
If d=4,
Therefore,
I think you can chose your own points like (0,296) and (2,592)
Answer:
raja don mein hoo kya problem he
The area of the parallelogram spanned by the given vectors is equal to the magnitude of their cross product.
(i + j + k) × (-2i + 3j + k)
= -2 (i × i) - 2 (j × i) - 2 (k × i)
… + 3 (i × j) + 3 (j × j) + 3 (k × j)
… + (i × k) + (j × k) + (k × k)
= - 2 (j × i) - 2 (k × i) + 3 (i × j) + 3 (k × j) + (i × k) + (j × k)
= 2 (i × j) - 2 (k × i) + 3 (i × j) - 3 (j × k) - (k × i) + (j × k)
= 5 (i × j) - 3 (k × i) - 2 (j × k)
= 5 k - 3 j - 2 i
Then the area of the parallelogram is
||-2 i - 3 j + 5 k|| = √((-2)² + (-3)² + 5²) = √38
Answer:
The coordinates of point D( 4,4)
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are E(10,4) and B(16,4)
'E' is the mid-point of segment BD
Let D(x₁, y₁) be a point
E = midpoint of segment BD
20 = x₁ + 16
20-16 = x₁
x₁ =4
<u><em>Step(ii):-</em></u>
4 + y₂ = 8
y₂ = 8-4 =4
The co-ordinates of point D( 4,4)