Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B
500(.25)=125 is the answer
Answer:
O No
Explanation:
Given equation: y = 13x + 12
To check if (2, 8) is a solution of the given equation.
Substitute x and y value in equation and check if it is true.
(x, y) = (2, 8)
simplify
This following statement is false and hence (2, 8) is not a solution.
Where is the picture? This question must have an picture/image
Answer:
13
Step-by-step explanation:
(x + 3)^3/2 = 64
√(x + 3)^3 = 64
(x + 3)^3 = 64^2
(x + 3)^3 = (4^3)^2
(x + 3)^3 = (4^2)^3
Same exponent
So
x + 3 = 4^2
x + 3 = 16
x = 13
