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2 years ago

Please help me sec theta - cos theta= sin^2 theta/ cos theta

Mathematics

2 answers:

inn [45]2 years ago

6 0

Answer:

Taking LHS

=1 by cos theta- cos theta

= (1- cos²0)/ cos0

= sin²0/ cos0 ( because 1-cos²0 is also equals to sin²0)

=RHS hence proved

kotykmax [81]2 years ago

3 0

Answer:

Step-by-step explanation:

Let theta be β.

So,

$sec\beta - cos\beta = \frac{sin^2\beta }{cos\beta } \\=>\frac{1}{cos\beta } - cos\beta = \frac{1 - cos^2\beta }{cos\beta } \\=>\frac{1 - cos^2}{cos\beta } = \frac{1 - cos^2\beta }{cos\beta }$

Here , identity used = $sin^2\beta + cos^2\beta = 1$

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2 years ago

This one is a tough one. If you can explain it to me that’ll me great.

Crazy boy [7]

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Please help me sec theta - cos theta= sin^2 theta/ cos theta​

Please help me sec theta - cos theta= sin^2 theta/ cos theta