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stepladder [879]
3 years ago
12

Please help me sec theta - cos theta= sin^2 theta/ cos theta​

Mathematics
2 answers:
inn [45]3 years ago
6 0

Answer:

Taking LHS

=1 by cos theta- cos theta

= (1- cos²0)/ cos0

= sin²0/ cos0 ( because 1-cos²0 is also equals to sin²0)

=RHS hence proved

kotykmax [81]3 years ago
3 0

Answer:

Step-by-step explanation:

Let theta be β.

So,

sec\beta - cos\beta = \frac{sin^2\beta }{cos\beta } \\=>\frac{1}{cos\beta } - cos\beta = \frac{1 - cos^2\beta }{cos\beta } \\=>\frac{1 - cos^2}{cos\beta } = \frac{1 - cos^2\beta }{cos\beta }

Here , identity used = sin^2\beta + cos^2\beta = 1

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