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stepladder [879]
3 years ago
12

Please help me sec theta - cos theta= sin^2 theta/ cos theta​

Mathematics
2 answers:
inn [45]3 years ago
6 0

Answer:

Taking LHS

=1 by cos theta- cos theta

= (1- cos²0)/ cos0

= sin²0/ cos0 ( because 1-cos²0 is also equals to sin²0)

=RHS hence proved

kotykmax [81]3 years ago
3 0

Answer:

Step-by-step explanation:

Let theta be β.

So,

sec\beta - cos\beta = \frac{sin^2\beta }{cos\beta } \\=>\frac{1}{cos\beta } - cos\beta = \frac{1 - cos^2\beta }{cos\beta } \\=>\frac{1 - cos^2}{cos\beta } = \frac{1 - cos^2\beta }{cos\beta }

Here , identity used = sin^2\beta + cos^2\beta = 1

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Mr. Baker wants to divide his class into smaller, equal-sized groups of students.However, he finds that his class cannot be divi
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Prime. Prime numbers can only be divided by the whole number, or one.

6 0
2 years ago
3% of what number is 1.86
Illusion [34]

Answer:

62

Step-by-step explanation:

Of means multiply and is means equals

.03 * n = 1.86

Divide each side by .03

.03n/.03 = 1.86/.03

n =62

8 0
2 years ago
The mean number of hours of study time per week for a sample of 562 students is 23. If the margin of error for the population me
Vadim26 [7]

Answer:

The 98% confidence interval for the mean number of hours of study time per week for all students is (20.9, 25.1).

Step-by-step explanation:

Confidence interval:

Sample mean plus/minus the margin of error.

In this question:

Mean of 23.

Margin of error 2.1.

Then

23 - 2.1 = 20.9

23 + 2.1 = 25.1

The 98% confidence interval for the mean number of hours of study time per week for all students is (20.9, 25.1).

3 0
2 years ago
Which could be the dimensions of a rectangular prism whose surface area is greater than 140 square feet? Select three options. 6
Murljashka [212]

Answer:

the second one, ((6 x 5) x 4) +((5 x 4) x 2) = 160

the third one, ((7 x 6) x 4) + (6 x 4) x 2) = 216

the fourth one, ((8 x 4) x 4) + ((4 x 3) x 2) = 152

Step-by-step explanation:

7 0
3 years ago
A bus went halfway from a village to a city at a certain speed. Then it stopped in traffic for an hour. In order to catch up the
k0ka [10]
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.

Since 200 km is "halfway", the total distance must be 400 km.

time = distance / speed
total time = (time for first half) + (delay) + (time for second half)

400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40

The speed of the bus before the traffic holdup was 40 km/h.
4 0
3 years ago
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