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Masja [62]
3 years ago
10

A Ferrari drove 300 kilometers in one and a half hours. How fast was the car going?

Mathematics
1 answer:
natita [175]3 years ago
4 0
We know, speed = distance / time
Here, distance = 300 Km
time = 1 1/2 h = 3/2 hour

Substitute their values, 
s = 300 / 3/2
s = 300*2 / 3
s = 600 / 3
s = 200 Km/h

In short, Your Answer would be 200 Km/h

Hope this helps!
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Tanner earns $14.50 per hour for the first 8 hours he works each day. For every hour worked over 8, he earns 1.75 of his normal
bogdanovich [222]

Answer:

167.19

14.50 x 8 = 116.00

14.50 + 1.75 = 16.25 per hour overtime

16.25 × 3.15 hour overtime = 51.19

116.00 + 51.19 = 167.19

Step-by-step explanation:

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mrs.jarvis made 49 long sleeved blouses for the girls choir she sews 11 buttons on the front panel and 2 buttons on each sleeve
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Answer:

she will need 735 buttons.

Step-by-step explanation:

11+2+2=15 buttons for each blouse

15x49=735 buttons total

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5x+2y=21<br> – 2x+6y=-34
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Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:(97/17,−64/17)

Equation Form: x=97/17, y=−64/17

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4. The population of Bay Village is 35,000 today. Every year the
frosja888 [35]

Answer:

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable y that is directly linked as a response to any changes of an independent variable x. The most common expression of such relationship would be y=ax where a is the relationship factor between y and x and is also known as the <em>slope </em>of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  b.

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call x and our fixed factor is the 750 increment which we will call a.  

From that we can conclude that:

<em>Year 1 Population: 35,000</em>

<em>Year 2 Population: 35,000 + 750 = 35,750</em>

<em>Year 3 Population: 35,750 + 750 = 36,500 </em>

And so on and so forth.<em> </em>

So we want to express the above as a Linear Model of the form:

<em> y = ax + b   </em>Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

y(x)=35,000+750x

Which for every different value of  x (i.e. every year) we can obtain the new and increased population  y(x).

7 0
3 years ago
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