Ask question

Ask question

All categories

3 years ago

5

The main tank has a radius of 70 feet. What is the volume of the quarter-sphered sized tank? Round your answer to the nearest wh

ole number.

1 answer:

Misha Larkins [42]3 years ago

8 0

Volume of a sphere with radius of 70 feet is:
$V = \frac{4}{3} * \pi * r^{3}$

where r is that radius

Because we need quarter sized tank of that radius we need to divide formula for volume by 4

Than we get:
$V = \frac{1}{3} * \pi * r^{3}$

V = 359188,76

Rounded:
V = 359189

You might be interested in

Colt1911 [192]

Answer:

1.5 seconds

Step-by-step explanation:

i took a test with the same question

6 0

3 years ago

Read 2 more answers

(4x) to the power of -4

Eva8 [605]

Answer:

3.90625×10^_03

Step-by-step explanation:

gshdieej

4 0

3 years ago

Find the next two terms of the sequence. 2,6,10,14,...

dimaraw [331]

The pattern is add 4

So the answer is C

6 0

3 years ago

Read 2 more answers

119. Beatrice decides to deposit $100 per month at the end of every month in a bank with an annual interest rate of 5.5% compoun

sveta [45]

Answer:

Beatrice will accumulate $1230.72 at the end of the year.

Step-by-step explanation:

We can write:

$(1+\frac{0.055}{12})=z$

$100=C$ for deposits

The first month would have only the deposit reflected in her balance, then, expanding some steps of the calculation would yield:

$S_{1}=C\\S_{2}=Cz + C\\S_{3}=Cz^{2}+Cz + C\\S_{n}=Cz^{n-1} +...+Cz+C$

A geometric series is given by:

$1+x+...+x^{m}=\frac{x^{m+1}-1}{x-1}$

Translating our series to the short form:

$S_{n}=C(\frac{z^{n}-1}{z-1} )$

plugin in the values for the 12 month gives:

$S_{12}=100(\frac{(1+\frac{0.055}{12})^{12} -1}{\frac{0.055}{12}})=1230.7169$

3 0

3 years ago

The time taken to deliver a pizza has a uniform probability distribution from 20 minutes to 60 minutes. What is the probability

Whitepunk [10]

Answer:

(1) The probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2a) The percentage of results more than 45 is 79.67%.

(2b) The percentage of results less than 85 is 91.77%.

(2c) The percentage of results are between 75 and 90 is 15.58%.

(2d) The percentage of results outside the healthy range 20 to 100 is 2.64%.

Step-by-step explanation:

(1)

Let <em>Y</em> = the time taken to deliver a pizza.

The random variable <em>Y</em> follows a Uniform distribution, U (20, 60).

The probability distribution function of a Uniform distribution is:

$f(x)=\left \{ {{\frac{1}{b-a};\ x\in [a, b] } \atop {0};\ otherwise} \right.$

Compute the probability that the time to deliver a pizza is at least 32 minutes as follows:

$P(Y\geq 32)=\int\limits^{60}_{32} {\frac{1}{b-a} } \, dx \\=\frac{1}{60-20} \int\limits^{60}_{32} {1 } \, dx\\=\frac{1}{40}\times[x]^{60}_{32}\\=\frac{1}{40}\times[60-32]\\=0.70$

Thus, the probability that the time to deliver a pizza is at least 32 minutes is 0.70.

(2)

Let <em>X</em> = results of a certain blood test.

It is provided that the random variable <em>X</em> follows a Normal distribution with parameters $\mu = 60$ and $s = 18$ .

The probabilities of a Normal distribution are computed by converting the raw scores to <em>z</em>-scores.

The <em>z</em>-scores follows a Standard normal distribution, N (0, 1).

(a)

Compute the probability that the results are more than 45 as follows:

$P(X>45)=P(\frac{X-\mu}{\sigma}> \frac{45-60}{18})=P(Z>-0.833)=P(Z$

The percentage of results more than 45 is: $0.7967\times100=79.67\%$

Thus, the percentage of results more than 45 is 79.67%.

(b)

Compute the probability that the results are less than 85 as follows:

$P(X$

The percentage of results less than 85 is: $0.9177\times100=91.77\%$

Thus, the percentage of results less than 85 is 91.77%.

(c)

Compute the probability that the results are between 75 and 90 as follows:

$P(75$

The percentage of results are between 75 and 90 is: $0.1558\times100=15.58\%$

Thus, the percentage of results are between 75 and 90 is 15.58%.

(d)

Compute the probability that the results are between 20 and 100 as follows:

$P(20$

Then the probability that the results outside the range 20 to 100 is: $1-0.9736=0.0264$ .

The percentage of results outside the range 20 to 100 is: $0.0264\times100=2.64\%$

Thus, the percentage of results outside the healthy range 20 to 100 is 2.64%.

4 0

3 years ago