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bazaltina [42]
2 years ago
10

For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed wi

th parameters q and M. For- mulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M.
Mathematics
1 answer:
8090 [49]2 years ago
7 0

Explanation:

Lets interpret Z with M trials. First we have M trials, each trial can be a success or not. The number of success is called N. Each trial that is a success becomes a trial, and if it is a success it becomes a success for Z. Thus, in order for a trial to be successful, it needs first to be successful for the random variable N (and it is with probability q), and given that, it should be a success among the N trials of the original definition of Z (with probability p).

This gives us that each trial has probability pq of being successful. Note that this probability is pq independently of the results of the other trials, because the results of the trials of both N and the original definition of Z are independent. This shows us that Z is the total amount of success within M independent trials of an experiment with pq probability of success in each one. Therefore, Z has Binomial distribution with parameters pq and M.

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Which of the following is the correct representation for a translation 8 units right and 4 units down?
Zolol [24]

Answer:

A. (x + 8, y - 4)

Step-by-step explanation:

When something is translated to the right, x goes up, and when something is translated down, y goes down.

Alternatively, eft means down for x and up means up for y.

5 0
3 years ago
What fraction is greater than 1/2. 4/6 3/8 1/3 2/5?
Andrei [34K]
1/2 = 0.5
4/6 =0.67
3/8=0.375
1/3=0.33
2/5=0.4 
There fore 1/2 is bigger :)
7 0
3 years ago
Help please ! Find the missing number in the table.
bulgar [2K]
If we take 771 to be the 100%, and increase it by 98%, thus 100% + 98% = 198.

now, if 771 is the 100%, what is the 198%?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
771&100\\
a&198
\end{array}\implies \cfrac{771}{a}=\cfrac{100}{198}\implies \cfrac{771\cdot 198}{100}=a
4 0
2 years ago
How could you solve this problem?
Rudiy27
I do A and B but that is the way I learned it. Hope this helps :)
7 0
3 years ago
Read 2 more answers
a line represented by y = 5x − 2 and a line perpendicular to it intersect at r(1, 3). what is the equation of the perpendicular
Snezhnost [94]
Y=ax+b, y=cx+d (a≠0, c≠0)
If the two line cross perpendicularly ⇔ ac= -1

So a tangent of the perpendicular line is "-(1/5)".

Then, the equation of the perpendicular line is y=-(1/5)x+a (a is <span> y-intercept</span>).

On the other hand, this equation pass r(1, 3), so 

3 = -(1/5) times 1 + a

∴ a=16 / 5 

Therefore, y=-(1/5)x+16 /5 is answer.

By the way, I'm Japanese so if you find some mistakes in my English, please let me know.


5 0
3 years ago
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