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Leya [2.2K]
3 years ago
12

5(x+3)can you tell me please

Mathematics
2 answers:
lesantik [10]3 years ago
7 0
If you're just looking for a formula, all you have to do is distribute the 5 to the x+3 to get 5x+15. If you're trying to find x, you would need to know what this formula equals to solve it.
-BARSIC- [3]3 years ago
5 0
What you do is you distribute the 5.

So your answer would be 5x+15
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Use the distributive property to write the following expressions in expanded form.
Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

a. 4x+4y

b. 8a+24b

c. 6x+33y

d. 63a+54b

e. 3ac+bc

f. 2xy+11yz

7 0
3 years ago
Copy the shape and fill in the missing angle. Sow the work. Thanks.
Otrada [13]

Answer:

x = -11

Step-by-step explanation:

Hello There!

create an equation

x + 51 + 60 + 80 = 180

combine like terms

51 + 60 + 80 = 191

x + 191 = 180

subtract 191 from each side

180 - 191 = -11

we're left with

x = -11

6 0
3 years ago
What is the rate of change of the following equation?<br> y = 5 X-3
Vadim26 [7]

Answer:Graph the line using the slope and y-intercept, or two points.

Slope:

5

y-intercept:

3

x

y

0

3

1

8

Step-by-step explanation:

7 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
4 years ago
Can someone help me with My Homework?
Julli [10]
2.5 bc JL is 5 that's the whole bottom of the triangle and ML is from center to right and vice versa.
4 0
3 years ago
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