To get the answer, you must solve 5656 / 3434 which = 1.64
The closest answer choice that matches this is the last one: 1 3/5 cup
Answer:Joanie watched 4/15 of the movie at night
Step-by-step explanation:
Let total amount of movie to watch = 1 whole since we are dealing with fractions
Amount of movie watched in the morning = 1/3
Amount watched at night = x
Amount remaining= 2/5
so that Total amount of movie to watch - Amount watched in morning and night = Amount remaining to watch
1 - ( 1/3 + x ) = 2/5
1- 2/5 = 1/3 + x
3/5 =1/3 + x
3/5 - 1/3 = x
9- 5/15 = x
x= Amount watched at night = 4/15
Using decimal multipliers, it is found that a rate of return of 5.2% in the third year will produce a cumulative gain of 16%.
The <u>decimal multiplier</u> for a increase of a% is given by:
In this problem, two increases of 5%, thus:
Another of x, that we want to find, and the result is a increase of 16%, thus:
The three increases(5%, 5% and x%) result in a increase of 16%, thus:
1.052 - 1 = 0.052
A rate of return of 5.2% in the third year will produce a cumulative gain of 16%.
A similar problem is given at brainly.com/question/21806362
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
