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Lubov Fominskaja [6]
3 years ago
12

Given that the length and width of a square is 4mm, what would the area be?

Mathematics
1 answer:
patriot [66]3 years ago
6 0

Answer:

16mm

Step-by-step explanation:

Area= length x width

4mm x 4mm

=16mm

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Pls pls help me I need it and the other one pls guys
snow_lady [41]

do u need all the answers?


3 0
3 years ago
Pyramid P is similar to pyramid Q. The volume of pyramid P is 980 c m cubed, and the volume of pyramid Q is 3307.5 c m cubed. Wh
jeka57 [31]

Answer:

The scale factor is \frac{3}{2}

Step-by-step explanation:

The volume of the original prism is V_P=980cm^3

The volume of the dilated prism is V_Q=3307.5cm^3

Let the scale factor be k.

To find the volume of the dilated prism, we multiplied by k^3.

\Rightarrow 980k^3=3307.5

\Rightarrow k^3=\frac{3307.5}{980}

\Rightarrow k^3=\frac{27}{8}

\Rightarrow k=\sqrt[3]{\frac{27}{8}}

\Rightarrow k=\frac{3}{2}

8 0
3 years ago
Lil fun for yall<br> what is the answer to this step by step?
Natasha_Volkova [10]

Answer:

194332.125 is the amount of interest

Step-by-step explanation:

7 0
3 years ago
The notation Ak meas the matrix A Multiplied with itself k times (a) For the 2×2 identity matrix I, show that I2 =I (b)For the n
djverab [1.8K]

Answer:

Entries of I^k are are also identity elements.

Step-by-step explanation:

a) For the 2×2 identity matrix I, show that I² =I

I^{2}=\left[\begin{array}{cc}1&0\\0&1\end{array}\right] \times \left[\begin{array}{cc}1&0\\0&1\end{array}\right] \\\\=\left[\begin{array}{cc}1\times 1+0\times 0&1\times 0+0\times 1\\0\times 1+1\times 0&0\times 0+1\times1\end{array}\right] \\\\=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Hence proved  I² =I

b) For the n×n identity matrix I, show that I² =I

n×n identity matrix is as shown in figure

Elements of identity matrix are

\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\

As square of 1 is equal to 1 so for n×n identity matrix I, I² =I

(c) what do you think the enteries of Ik are?

As mentioned above

\delta I_{ij}=1\quad if\quad i=j\\\delta I_{ij}=0\quad if\quad i\ne j\\

Any power of 1 is equal to 1 so kth power of 1 is also 1. According to this Ik=I

6 0
3 years ago
Prove: ∠1 and ∠14 are supplementary angles.
Zigmanuir [339]

Answer:

can you please send the images of figure of these angle

3 0
2 years ago
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