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3 years ago

How to divide a whole number by a fraction?

2 answers:

6 0

<span>Multiply the bottom number of the fraction by the whole number.<span>Simplify the fraction (if needed)

Hope this helps. :)

</span></span>

Iteru [2.4K]3 years ago

6 0

Make the whole number a fraction by putting a 1 under it.
Example:
in 12 divided by 2/3 it be.
12/1 divided bye 2/3.
then when it is set up like this:
12 2
--- / --- =
1 3
you cross multiply ;)

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Which expression is equivalent to 36x^12

m_a_m_a [10]

The correct answer is C

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4 years ago

3. Suppose that you draw two cards from a standard 52 card deck. You replace the first card and shuffle thoroughly before you dr

Kruka [31]

Answer:

$\text{a)} \frac{1}{17} \text{b)} \frac{1}{221}\text{c)}\frac{12}{13}\text{d)}\frac{188}{221}$

Step-by-step explanation:

GIVEN: You draw two cards from a standard $52$ card deck. You replace the first card and shuffle thoroughly before you draw the second.

TO FIND: a) What is the probability that the first card is $7$ b) What is the probability that both cards are

SOLUTION:

Let $\text{A}$ and $\text{B}$ be two events such that

$\text{A}$ $=\text{first card drawn is 7}$

$\text{B}$ $=\text{Second card is 7}$

$\text{probability that first card is 7 =P(A)}$

<h3> $\text{P(A)}=\frac{\text{total 7 numbered cards}}{\text{total cards in deck}}$ </h3><h3> $\text{P(A)}=$ $\frac{4}{52}=\frac{1}{13}$ </h3>

$\text{probability that first card is 7 =P(A)}$

$\text{probability that both cards are 7}=$ $\text{first card is 7}\times\text{second card is 7}$

$\text{probability that both cards are 7}=$ $\text{P(A).P(B)}$

$\text{P(B)}=\frac{\text{total number of 7 numbered cards left}}{\text{total number of cards in deck left}}$

$\text{P(B)}=\frac{3}{51}=\frac{1}{17}$

$\text{probability that both cards are 7}=$ $\frac{1}{13}\times\frac{1}{17}$

$\text{probability that both cards are 7}=$ $\frac{1}{221}$

$\text{probability that first card is not 7}=1-\text{probability that first card is 7}$

$\text{probability that first card is not 7}=$ $1-\text{P(A)}$

$\text{probability that first card is not 7}=$ $1-\frac{1}{13}$

$\text{probability that first card is not 7}=$ $\frac{12}{13}$

$\text{probability that both cards are not 7}=$ $(\text{first card is not 7}).(\text{second card is not 7})$

$\text{probability that both cards are not 7}=$ $\text{[1-P(A)].[1-P(B)]}$

$\text{P(B)}=\frac{\text{total 7 numbered cards}}{\text{total cards left in deck}}$

$\text{probability that both cards are not 7}=$ $(1-\frac{1}{13})\times(1-\frac{4}{51})$

$\text{probability that both cards are not 7}=$ $\frac{12}{13}\times\frac{47}{51}$

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