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attashe74 [19]
3 years ago
11

I have f(x)=x^2+x+5. Then (f(x)-f(a))/(x-a).

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

  (f(x) -f(a))/(x -a) = x +a +1

Step-by-step explanation:

(f(x) -f(a))/(x -a) = ((x^2 +x +5) -(a^2 +a +5))/(x -a) = (x^2 -a^2 +x -a)/(x -a)

  = ((x -a)(x +a) +(x -a))/(x -a) = x +a +1

(f(x) -f(a))/(x -a) = x +a +1

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3 years ago
4.18 repeating as a fraction
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Answer: it’s 148 also i don’t know if you mean 4.18 as a fraction?

Step-by-step explanation:

6 0
3 years ago
Writetwo ways you could use to find 5+8
Igoryamba

5+8=13

or

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5 0
3 years ago
Read 2 more answers
Of all the people applying for a certain​ job, 80% are qualified and 20​% are not. The personnel manager claims that she approve
motikmotik

Answer:

69.23% probability that a person is not qualified if he or she was not approved by the manager.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes:

In this problem, we have these following probabilities:

80% probability that a person is qualified

20% probability that a person is not qualified.

90% probability that a qualified person is approved.

10% probability that a qualified person is not approved.

10% probability that an unqualified person is approved.

90% probability that an unqualified person is not approved.

Find the probability that a person is not qualified if he or she was not approved by the manager.

Desired outcomes

Unqualified and not approved.

20% are not qualified. Of those, 90% were not approved. So

0.9*0.2 = 0.18

Total outcomes:

Qualified and not approved or unqualified and not approved.

80% are qualified. Of those, 10% were not approved

20% are not qualified. Of those, 90% were not approved. So

0.8*0.1 + 0.9*0.2 = 0.26

Probability

P = \frac{0.18}{0.26} = 0.6923

69.23% probability that a person is not qualified if he or she was not approved by the manager.

7 0
3 years ago
In a study with four groups and 10 participants in each group, the sum of squares for the between-groups source of variation is
Stells [14]

Answer:

20

Step-by-step explanation:

Given that:

The study group n = 4

number of participants = 10

the sum of squares for the between-groups source of variation is  60

The objective is to determine the mean square  between groups in this study

The mean square  between groups in this study compares the means of the group with the  sum of squares for the between-groups source (i.e the grand mean)

For this analysis;

the degree of freedom = n-1

the degree of freedom = 4 - 1

the degree of freedom =  3

Thus; the mean square between groups = \dfrac{60}{3}

the mean square between groups = 20

7 0
3 years ago
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