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Dovator [93]
4 years ago
14

X^2+2x-5=0 quadratic form

Mathematics
1 answer:
julsineya [31]4 years ago
3 0

Answer:

-1+√6

-1-√6

Step-by-step explanation:

x²+2x-5=0

x=(-2±√(2²-4(-5)))/2=(-2±√(4+20))/2=(-2±√24)/2

x₁=(-2+√24)/2 or x₂=(-2-√24)/2

x₁=(-2+2√6)/2 or (-2-2√6)/2

x₁=-1+√6 or x₂=-1-√6

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3 years ago
Determine the number of terms, n, given the geometric series -1 - 2 - 4 - 8 - ... and Sn=−31.
Gemiola [76]

Answer:

5

Step-by-step explanation:

We are given the geometric series:

-1, - 2, - 4, - 8.......

In the geometric series above, the common ratio = second term/first term = -2/-1

= 2

Where common ratio is greater than 1(r >1)

The sum of a geometric progression =

Sn = a(rⁿ -1)/r - 1

In the question we are asked to find the number of term = n

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a = -1

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Hence,

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-31 = -1(2ⁿ - 1)

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2ⁿ = 1 + 31

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n = 5

Therefore, the number of terms(n) = 5

3 0
3 years ago
What is the answer to 2+4×7
PIT_PIT [208]
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