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Ksju [112]
4 years ago
6

Round to the nearest hundredth 2.815

Mathematics
1 answer:
LenaWriter [7]4 years ago
8 0
2.82 is the answer, ...
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Mariah was playing a game where she gets a point if her spinner lands on a multiple of 3. What is the probability that she will
DedPeter [7]

Answer:

She has a 67% chance of getting anything other than a multiple of 3.

Step-by-step explanation:

8 to 4

7 0
3 years ago
B Christian installed an electric pump to pump water from a borehole into a 30 000 litre cement dam. If the water is pumped at a
skelet666 [1.2K]

Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.

Option B)6h 40min is the correct answer.

<h3>How long does it take to fill the dam?</h3>

Given that;

  • Amount of water needed to fill the dam A = 30000 litres
  • Pump rate r = 75 litres per minute
  • Time needed to fill the dam T = ?

To determine how long it take to fill the dam, we say;

Time need = Amount of water needed ÷ Pump rate

T = A ÷ r

T = 30000 litres ÷ 75 litres/minute

T = 400 minutes

Note that; 60min = 1hrs

Hence,

T = 6hours 40minutes

Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.

Option B)6h 40min is the correct answer.

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8 0
2 years ago
What is the median of 36,14,21,39,11,2​
Usimov [2.4K]

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4 0
3 years ago
Read 2 more answers
Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter
Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

Step-by-step explanation:

To solve this we have to find the missing sides to each of the triange discribed in prenthesis thus

A we have the sides of the triangle given by x, 8 and  \sqrt{8^{2} - x^{2} }or  \sqrt{64 - x^{2} }

thus tan(arcsin(x/8))  = \frac{x}{\sqrt{64 - x^{2} }}  =

Therefore  ........tan(arcsin(x/8))  =......x/sqrt(64-x^2)

B

Here we have cos = adjacent/hypotenuse where adjacent side is \sqrt{64 - x^{2} } and hypothenuse = 8 we have \sqrt{64 - x^{2} }/8

B .      cos (arsin (x/8))  ....sqrt(64-x^2)/8

4 0
3 years ago
Someone please help with 9th question !!!!
meriva

LIMITS  \:  \: AND \:  \:  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  DERIVATIVES


Heya !

Check the attachment.
Hope it helps you :)

5 0
3 years ago
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