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RUDIKE [14]
3 years ago
9

What is 2/3 of 261.46??

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0
You can solve this by multiplying 261.46 by 2/3.

261.46*2/3=174.306
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(2x^2)+7x+5=0, I do not understand the -5/2 part why is it negative please elaborate
mamaluj [8]

Answer:

It is one of the answers of the quadratic expression.

Step-by-step explanation:

There are two answers (because it has exponents, you can have two answers)

-1, -2.5  or  -5/2

5 0
3 years ago
WORTH 99 POINTS!
Ksivusya [100]
The general formula for the lateral surface area of a regular pyramid is:
A= \frac{1}{2} *p*l
Where:
p=perimeter of a base
l=slant height

a.
a=3ft
l=4ft
p=5*a=5*3=15ft
A= \frac{1}{2} *15*4=30 ft^{2}

b.
a=2.5ft
l=4ft
p=6*a=6*2.5=15ft
A= \frac{1}{2} *15*4=30 ft^{2}

c.
a=1.9ft
l=4ft
p=8*a=8*1.9=15.2ft
A= \frac{1}{2} *15.2*4=30.4 ft^{2}

d.
Based on a lateral surface area the blue umbrella is best choice. But, the best umbrella overall is the one with the greatest base area. General formula for regular polygon is:
A= \frac{1}{4} *n* a^{2}*cot( \frac{180}{n} )

For pentagon:
A=15.48ft^2
For hexagon:
A=16.24ft^2
For octagon:
A=17.43ft^2
Blue umbrella is still best choice.
8 0
3 years ago
Read 2 more answers
Emilio has 5 bags of bird seeds each bag has about 28 ounces of bird seeds if he divides the bird seeds equally into 3 container
aniked [119]
28 * 5 = 140/3 = 46.6
Hope this helped!!
7 0
3 years ago
Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up
Artyom0805 [142]

Answer:

In the long run, ou expect to  lose $4 per game

Step-by-step explanation:

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.

Assuming X be the toss on which the first head appears.

then the geometric distribution of X is:

X \sim geom(p = 1/2)

the probability function P can be computed as:

P (X = n) = p(1-p)^{n-1}

where

n = 1,2,3 ...

If I agree to pay you $n^2 if heads comes up first on the nth toss.

this implies that , you need to be paid \sum \limits ^{n}_{i=1} n^2 P(X=n)

\sum \limits ^{n}_{i=1} n^2 P(X=n) = E(X^2)

\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+(\dfrac{1}{p})^2        ∵  X \sim geom(p = 1/2)

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+\dfrac{1}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p+1}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-p}{p^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-\dfrac{1}{2}}{(\dfrac{1}{2})^2}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{4-1}{2} }{{\dfrac{1}{4}}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{3}{2} }{{\dfrac{1}{4}}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ 1.5}{{0.25}}

\sum \limits ^{n}_{i=1} n^2 P(X=n) =6

Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6

= $4

∴

In the long run, you expect to  lose $4 per game

3 0
4 years ago
Find the value of the expression x3−y3+x2+y2+3 by substituting x=−2 and y=1.
vaieri [72.5K]

\\ \sf\dashrightarrow x^3-y^3+x^2+y^2+3

\\ \sf\dashrightarrow (-2)^3-(1)^3+(-2)^2+(1)^2+3

\\ \sf\dashrightarrow -8-1+4+1+3

\\ \sf\dashrightarrow -9+8

\\ \sf\dashrightarrow -1

8 0
3 years ago
Read 2 more answers
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