Answer:
You can spend 4 days in Los Angeles and 3 days in San Francisco.
Step-by-step explanation:
From the information given, you can write the following equations:
x+y=7 (1)
275x+400y=2,300 (2), where:
x is the number of days to visit Los Angeles
y is the number of days to visit San Francisco
First, you can solve for x in (1):
x=7-y (3)
Now, you can replace (3) in (2):
275(7-y)+400y=2,300
1,925-275y+400y=2,300
125y=2,300-1,925
125y=375
y=375/125
y=3
Finally, you can replace the value of y in (3) to find x:
x=7-3
y=4
According to this, the answer is that you can spend 4 days in Los Angeles and 3 days in San Francisco.
Answer:
there is a thing called you can use that
Step-by-step explanation:
Well, 18 yards is 54 feet.
The true statement is Peter walks at a rate of 13 over 4 miles per hour.
<h3>What is the true statement?
</h3>
Direct variation is when two variables move in the same direction. If one variable increases, the other variable increases. When the hour Peter walks increases, the distance he walks also increases.
Here are the options:
Peter walks at a rate of StartFraction 4 over 13 EndFraction miles per hour.
Peter walks at a rate of 4 miles per hour.
Peter walks at a rate of StartFraction 13 over 4 EndFraction miles per hour.
Peter walks at a rate of 13 miles per hour.
To learn more about direct variation, please check: brainly.com/question/27573249
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Answer:
The probability that a part was manufactured on machine A is 0.3
Step-by-step explanation:
Consider the provided information.
It is given that Half of a set of parts are manufactured by machine A and half by machine B.
P(A)=0.5
Let d represents the probability that part is defective.
Ten percent of all the parts are defective.
P(d) = 0.10
Six percent of the parts manufactured on machine A are defective.
P(d|A)=0.06
Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective
:



Hence, the probability that a part was manufactured on machine A is 0.3