X=8.5
190-5=185
185/-5=-37
-37-3=-34
34/4=8.5
Answer:
There are 110 children total in the sports club
Step-by-step explanation:
To get this answer, its actually easier than it seems. You might need a calculator however.
First you start with the 11 children who play both badminton and squash, then, you divide that by 0.25 (25%) to get 44.
Next you take 44 and divide it by 0.4 (40%) to get 110.
And there you go! If you want to make sure you got it right simply start with 110 and multiply it by 0.4 then multiply the number/decimal you get by 0.25. You should get 11 to confirm your answer :)
Answer:
22,000
Step-by-step explanation:
4%/100=0.04
0.04*50,000=20,000 || 130,000-50,000=80,000 ||
2%/100=0.02
0.02*100,000= 2,000 || 80,000 - 100,000 ||
To explain it simply, Rosie receives 20,000 in commission for the first 50,000 of the sale. However, she sold a property for 130,000 meaning she also receives 2,000 for the next 100,000. Therefore she receives $22,000 in total on her $130,000 sale.
Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when 




Upper limit
X when Z has a pvalue of 0.80. So X when 




11 and 12
7 and 512
12 and 10
0 and 78
left side numerator
right side denominator