Answer with Step-by-step explanation:
The height of the ball from the ground as a function of time is given by
![h(t)=-16t^2+80t+4](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E2%2B80t%2B4)
The height of the ball at any instant of time can be found by putting the value of time 't' in the above relation as
Part a)
Height of ball after 2 seconds it is released is
![h(2)=-16\times 2^2+80\times 2+4=100feet](https://tex.z-dn.net/?f=h%282%29%3D-16%5Ctimes%202%5E2%2B80%5Ctimes%202%2B4%3D100feet)
Part b)
Height of ball after 4 seconds it is released is
![h(4)=-16\times 4^2+80\times 4+4=68feet](https://tex.z-dn.net/?f=h%284%29%3D-16%5Ctimes%204%5E2%2B80%5Ctimes%204%2B4%3D68feet)
This is all I got. Hope this helps:
(2,716 feet) x (1mile / 5,280 feet) = <em>0.5144 mile</em> (rounded)
Answer:
14
Step-by-step explanation:
56/4=14
Check
14*4=56