Answer:
f(N) = 2+ N/2 + 6N² units of time.
Step-by-step explanation:
Assigning 0 to the variable sum takes one unit of time.
Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have
f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).
Answer:
Change 45 min to .75 hrs
Distance = speed * time
Train A's distance = 55(t+.75)
Train B's distance = 70t
The equation
D(t) = 70t + 55(t+.75)
Answer:
a. 6
b. 9
c. 4
Step-by-step explanation:
a.
Range = greatest - smallest
Range = 85 - 79
Range = 6
b.
b > 81
82, 83, 84...
3 82s
4 83s
2 85s
3 + 4 + 2 = 9
c.
b = 83
4 83s
4
wheee
Compute each option
option A: simple interest
simple interest is easy
A=I+P
A=Final amount
I=interest
P=principal (amount initially put in)
and I=PRT
P=principal
R=rate in decimal
T=time in years
so given
P=15000
R=3.2% or 0.032 in deecimal form
T=10
A=I+P
A=PRT+P
A=(15000)(0.032)(10)+15000
A=4800+15000
A=19800
Simple interst pays $19,800 in 10 years
Option B: compound interest
for interest compounded yearly, the formula is
where A=final amount
P=principal
r=rate in decimal form
t=time in years
given
P=15000
r=4.1% or 0.041
t=10
use your calculator
A=22418.0872024
so after 10 years, she will have $22,418.09 in the compounded interest account
in 10 years, the investment in the simple interest account will be worth $19,800 and the investment in the compounded interest account will be worth$22,418.09
<span>√9/49
First you figure out the square root of 9 which is 3 since 3 x 3 equals 9. Then you find the square root of 49 which is 7 since 7 x 7 equals 49. Therefore, the answer is 3/7</span>
