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-BARSIC- [3]
3 years ago
12

What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0?

Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

(6,1)

Step-by-step explanation:

Just look for the terms with x and y in them. Divide their coefficients by two, and multiply by -1. And then put them in an ordered pair.

So in this case, -12x --> 6 and -2y --> 1

Obviously the more orthodox way would be to actually complete the square, but I'm lazy, this way is faster, and since this seems to be multiple choice, as long as you have the correct answer, it shouldn't matter.

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3 years ago
If the sinø=7/12, what is cosø?
777dan777 [17]

Answer:

If the sinø=7/12, cosø is \frac{\sqrt{95} }{12}

Step-by-step explanation:

We are given sinФ = 7/12

We need to find cosФ

The basic trigonometric functions of right triangle are:

sin\theta=\frac{opposite}{hypotenuse}

cos\theta=\frac{adjacent}{hypotenuse}

We need values of adjacent and hypotenuse to find cosФ

Using Pythagoras theorem we can find the value of adjacent

(Hypotenuse)^2= (Opposite)^2+(Adjacent)^2

We have Hypotenuse= 12 and Opposite = 7 (because sin\theta=\frac{opposite}{hypotenuse} and we are given sin\theta=\frac{7}{12}

Inserting values and finding adjacent:

(Hypotenuse)^2= (Opposite)^2+(Adjacent)^2\\(12)^2=(7)^2+(Adjacent)^2\\144=49+(Adjacent)^2\\144-49=(Adjacent)^2\\95=(Adjacent)^2\\\sqrt{(Adjacent)^2} =\sqrt{95}\\Adjacent=\sqrt{95}

So, value of Adjacent is \sqrt{95}

Now finding cosФ

cos\theta=\frac{adjacent}{hypotenuse}

Adjacent = \sqrt{95}, hypotenuse = 12

cos\theta=\frac{\sqrt{95} }{12}

So, If the sinø=7/12, cosø is \frac{\sqrt{95} }{12}

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3 years ago
X/√24-√150/4=3√96/16
geniusboy [140]
I hope this helps you

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4 years ago
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