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3 years ago

What is the unit rate for 150:6?

Mathematics

1 answer:

shusha [124]3 years ago

6 0

Answer: htru3bebfuewbfebfh im smart :)

Step-by-step explanation:

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Please help!!!!!!!!!!

steposvetlana [31]

9514 1404 393

Answer:

-203.1875

Step-by-step explanation:

The ends of the interval are ...

(-4, g(-4)) = (-4, 1023 15/16)

(1, g(1)) = (1, 8)

The average rate of change is the slope of the line between these two points:

m = (y2 -y1)/(x2 -x1)

m = (8 -(1023 15/16))/(1 -(-4)) = (-1015 15/16)/5 = -203 3/16

The average rate of change on the interval is -203 3/16.

5 0

3 years ago

Does anyone know this answer??

Aleonysh [2.5K]

For this case we have the following equation:

$(2x + 3) ^ 2 + 8 (2x + 3) + 11 = 0$

Let $u = 2x + 3$

We have:

$u ^ 2 + 8u + 11 = 0$

By definition, given an equation of the form $ax ^ 2 + bx + c = 0$

The quadratic formula, to find the solution can be written as:

$x = \frac{-b+/-\sqrt{b ^ 2-4 (a) (c)} }{2(a)}$

In this case we have:

$a = 1\\b = 8\\c = 11$

Substituting in the quadratic formula we have:

See attached image

Answer:

Option B

8 0

3 years ago

Read 2 more answers

Is the number of miles to the next service station and the number of kilometers linear

evablogger [386]

I need a photo to tell you the answer

7 0

4 years ago

The temperature today was 10 degrees colder than twice yesterday's temperature, t.

Aneli [31]

Answer: Today's temperature : 2t -10

Step-by-step explanation:

Hi, to write the expression of the statement given we have to analyze each phrase:

<em>Twice yesterday's temperature, t.</em> If t is yesterday’s temperature, twice that temperature equals 2t.

<em>The temperature today was 10 degrees colder than</em>: It means that we have to subtract 10 degrees :(-10)

Mathematically speaking:

Today's temperature : 2t -10

where t = yesterday's temperature

Feel free to ask for more if needed or if you did not understand something.

5 0

4 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is:

$(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})$

$(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]$

$(x,y) = (10.452, 34.531)\,[km]$

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

$\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}$

$\theta \approx 16.840^{\circ}$

And the distance from the camp is calculated by the Pythagorean Theorem:

$r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}$

$r = 36.078\,km$

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0

3 years ago