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Lemur [1.5K]
3 years ago
5

What is the length of the diagonal in a rectangular prism that measures 8mm by 14mm by 6m? Round your answer to the nearest tent

h
Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

17.2

Step-by-step explanation:

It's kinda like the pythagorean theorem where you square the sides, add them, and then square root the answer. I hope this is correct

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Step-by-step explanation:

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3 0
3 years ago
A scientist claims that 9% of viruses are airborne.
Aleksandr [31]

Answer:

The probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% is 0.006.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\mu_{\hat p}=p  

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The information provided is:

<em>n</em> = 596

<em>p </em>= 0.09

As the sample size is quite large, i.e. <em>n</em> = 596 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by a Normal distribution.

The mean and standard deviation are:

\mu_{\hat p}=p=0.09\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.09(1-0.09)}{596}}=0.012

Compute the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% as follows:

P(\hat p-p>0.03)=P(\hat p>0.12)

                         =P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}>\frac{0.12-0.09}{0.012})\\\\=P(Z>2.5)\\\\=1-P(Z

Thus, the probability that the sample proportion of airborne viruses in differ from the population proportion by greater than 3% is 0.006.

5 0
3 years ago
Perform the indicated operation.<br> (c 2 + 2c - 35) ÷ (c - 5)
deff fn [24]
(c²+2c-35): (c-5)
Ruffini´s rule:

             1              2              -35

5                           5                35  
-------------------------------------------------
             1              7                  0


(c²+2c-35): (c-5)=(c+7)

4 0
3 years ago
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