It has exactly one solution.
If you graph both of these equations on desmos, you will see that they only cross once. Therefore you only have one solution
The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
A plane that travels a distance
, in kilometers, with a bearing of
sexagesimal degrees can be represented in standard position by means of the following expression:
(1)
We can obtain the resulting vector (
) by the principle of superposition:
(2)
If we know that
,
,
,
,
and
, then the resulting vector is:

![\vec R = (5\sqrt{3}, 6) \,[km]](https://tex.z-dn.net/?f=%5Cvec%20R%20%3D%20%285%5Csqrt%7B3%7D%2C%206%29%20%5C%2C%5Bkm%5D)
The magnitude of the resultant is found by Pythagorean theorem:

And the bearing is determined by the following <em>inverse</em> trigonometric relationship:
(3)
If we know that
and
, then the magnitude and the bearing of the resultant is:




The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.
To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479
Answer:
See proof below
Step-by-step explanation:
If C is the midpoint of AB, then AC = CB
Given
AC=7x−10;
CB=3x+10
Then 7x - 10= 3x+10
Add 10 to both sides
7x-10+10 = 3x +10+10
7x = 3x + 20
7x - 3x = 10+10
4x = 20
x = 20/4
x = 5
Get AC
AC = 7x - 10
AC= 7(5) - 10
AC = 35-10
AC = 25 (Proved)
Add 1/6 teaspoon and 1/8 teaspoon. The LCD here is 24, so we're adding
4/24 to 3/24, obtaining 7/24 (teaspoon of pepper, total).