Ask question

Ask question

All categories

2 years ago

5

What is the length of the diagonal in a rectangular prism that measures 8mm by 14mm by 6m? Round your answer to the nearest tent

h

1 answer:

nevsk [136]2 years ago

6 0

Answer:

17.2

Step-by-step explanation:

It's kinda like the pythagorean theorem where you square the sides, add them, and then square root the answer. I hope this is correct

You might be interested in

Which statement describes the solution to the system of equations?

Murrr4er [49]

It has exactly one solution.
If you graph both of these equations on desmos, you will see that they only cross once. Therefore you only have one solution

8 0

3 years ago

Read 2 more answers

a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 1

Virty [35]

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

A plane that travels a distance $r$ , in kilometers, with a bearing of $\theta$ sexagesimal degrees can be represented in standard position by means of the following expression:

$\vec r = r\cdot (\sin\theta, \cos \theta)$ (1)

We can obtain the resulting vector ( $\vec R$ ) by the principle of superposition:

$\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})]$ (2)

If we know that $r_{1} = 5\,km$ , $\theta_{1} = 0^{\circ}$ , $r_{2} = 6\,km$ , $\theta_{2} = 60^{\circ}$ , $r_{3} = 4\,km$ and $\theta_{3} = 120^{\circ}$ , then the resulting vector is:

$\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})$

$\vec R = (5\sqrt{3}, 6) \,[km]$

The magnitude of the resultant is found by Pythagorean theorem:

$\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}$

And the bearing is determined by the following <em>inverse</em> trigonometric relationship:

$\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right)$ (3)

If we know that $R_{x} = 5\sqrt{3}\,km$ and $R_{y} = 6\,km$ , then the magnitude and the bearing of the resultant is:

$\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}$

$\|\vec R\| \approx 10.536\,km$

$\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)$

$\theta_{R} \approx 34.715^{\circ}$

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479

6 0

2 years ago

Val is going to plant d vegetable seeds in one garden and 3d + 8 vegetable seeds in another. How many seeds is Val going to pla

konstantin123 [22]

D = 11 seeds planted

8 0

3 years ago

Read 2 more answers

Given: Point C is the midpoint of AB¯¯¯¯¯.

suter [353]

Answer:

See proof below

Step-by-step explanation:

If C is the midpoint of AB, then AC = CB

Given

AC=7x−10;

CB=3x+10

Then 7x - 10= 3x+10

Add 10 to both sides

7x-10+10 = 3x +10+10

7x = 3x + 20

7x - 3x = 10+10

4x = 20

x = 20/4

x = 5

Get AC

AC = 7x - 10

AC= 7(5) - 10

AC = 35-10

AC = 25 (Proved)

3 0

2 years ago

Grandma put 1⁄6 teaspoon of pepper into the soup. After tasting the soup, she added 1⁄8 teaspoon of pepper. How much pepper is i

alexandr1967 [171]

Add 1/6 teaspoon and 1/8 teaspoon. The LCD here is 24, so we're adding
4/24 to 3/24, obtaining 7/24 (teaspoon of pepper, total).

3 0

3 years ago