Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
There’s no picture or anything.
Answer:
2 2/3
Step-by-step explanation:
Make them into improper fractions first.
11/2 - 17-6
Then multiply 11/2 so that they have common denominators.
33/6 - 17/6
Then solve.
33/6 - 17/6 = 16/6
Then convert back into a mixed number.
2 4/6 or 2 2/3
Answer:
1
1
0
0
Step-by-step explanation:
here´s and example for 1
1⁵
1x1x1x1x1=1
so 1 raised to the power of any number is 1
1 multiply by itself any number of times is 1
here´s an example for 0
0⁴
0x0x0x0=0
hence, the vale of 0 raised to any power is 0.
0 multiplied by itself any number of times is 0
Answer:
-4
Step-by-step explanation:
