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3 years ago

Work out the sum of 5.6 and 319.71.

Mathematics

1 answer:

astraxan [27]3 years ago

4 0

Sum means addition.

5.6 + 319.71

.71 + .6 = 1.31

319 + 5 = 324

324 + 1.31 = 325.31

The sum is 325.31

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Given that a trapezoid has the following dimensions, find the area. Area = ________ units2

rjkz [21]

The formula for the area of a trapezoid is A = a+b/2 * h. So just plug in the dimensions.
A = 5 + 3/2 * 5
A = 8/2 * 5
A = 4 * 5
A = 20 units²
I hope this helps love! :)

8 0

3 years ago

What is the area of the shape below

Bad White [126]

Answer:

The area of the shape is $A=886 \:cm^2$ .

Step-by-step explanation:

The shape in the graph is a composite figure is made up of several simple geometric figures such as triangles, and rectangles.

Area is the space inside of a two-dimensional shape. We can also think of area as the amount of space a shape covers.

To calculate the area of a composite shape you must divide the shape into rectangles, triangles or other shapes you can find the area of and then add the areas back together.

First separate the composite shape into three simpler shapes, in this case two rectangles and a triangle. Then find the area of each figure.

To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.

The area of the first rectangle is $A=34\cdot 16=544\:cm^2$

The area of the second rectangle is $A=11\cdot19=209\: cm^2$

The area of a triangle is given by the formula $A=\frac{1}{2} bh$ where <em>b</em> is the base and <em>h</em> is the height of the triangle.

The area of the triangle is $A=\frac{1}{2} \cdot 14\cdot19=133\:cm^2$

Finally, add the areas of the simpler figures together to find the total area of the composite figure.

$A_{composite\:shape}=544+209+133=886 \:cm^2$

3 0

4 years ago

Help

Anika [276]

The answer to your question is D
.5 x 8= 4 pounds
.5 x 10=5 pounds
.5 x 12=6 pounds
.5 x 16=8 pounds

3 0

3 years ago

Read 2 more answers

insects have 6 legs,and spiders have 8 legs.What is the least number of insects and the least number of spiders possible so that

iogann1982 [59]

By using LCF (Least common factor), the answer would be 24. If you count by sixes and eighteen, the first number they have the same is 24. 6,12,18,24
8,16,24

7 0

3 years ago

Read 2 more answers

A rectangular field is 95 meters long and 65 meters wide. Give the length and width of another rectangular field that has the sa

Lena [83]

Answer:

There are a ton of answers. For instance, 1m by 159m.

Step-by-step explanation:

The formula for the area is $a=l*w$ , where $l$ and $w$ are constants.

The formula for perimeter is $p=2l+2w$

The question wants another rectangle that has the same perimeter, but a smaller area.

The perimeter of the two fields has to be:

$p=(2*95)+(2*65)\\p=190+130\\p=320$

Thankfully, the question never specified how much smaller the area has to be. So let's go to the logical extreme and make it 1 meter wide. To conserve the perimeter, we'd have to add the removed 64 meters to the original 95 meters of length, resulting in a rectangle with a width of 1m and a length of 159m. This results in an area of exactly 159 $m^{2}$ . The original rectangle had an area of 6175 $m^{2}$ . Mission accomplished!

But why stop there? Let's go even further down this rabbit hole!

Instead of 1, why don't we take it several steps further and use 0.0000001? At that point, the length would end up being 159.9999999m.

The area would be 0.00001599999999 $m^{2}$ .

Let's go further!!

Width: 0.00000000000000000001

Length: 159.99999999999999999999

Area: 0.00000000000000000001599999999999999999999 (approximate).

One more, for old time's sake.

Width: 0.00000000000000000000000000000000000000000000000001m

Length: 159.99999999999999999999999999999999999999999999999999m

Area: 0.00000000000000000000000000000000000000000000000015999999999999999999999999999999999999999999999999999 $m^{2}$

At that point, there's so little area in the plot of land that you could claim it has no area!

5 0

3 years ago