This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Rewriting the equation as a quadratic equation equal to zero:
x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
(x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
x + 5 = 0 => x = -5
x - 6 = 0 => x = 6
Therefore, our solutions are x = -5 and x = 6.
Answer:
<u><em>Vertical angles are</em></u><u><em> congruent</em></u><u><em>, so the</em></u>
<u><em>equation </em></u><u><em>3x-6 = 114</em></u><u><em> can be used to find x.</em></u>
<u><em>The value of x is </em></u><u><em>40</em></u><u><em>.</em></u>
<u><em /></u>
<u><em>Convince Me!</em></u>
<u><em>Why can you use an equation when solving for x in</em></u>
<u><em>the diagram?</em></u>
<u><em>You can use the eqution because they are equal to each other. When they are equal to each other, you can find x by using the equation to simplify and get x alone.</em></u>
Answerno idea
Step-by-step explanation:
