Answer:
a = 1565217.39 ft / s ^ 2
t = 0.001725 seconds
Step-by-step explanation:
The first thing is to use the same system of units therefore we will pass the 28 inches to feet, like this:
28 in * (1 ft / 12 in) = 2.33 ft
Now yes, we can continue, we have the following data:
vi = 0
vf = 2700 ft / s
the equations in this case are as follows:
vf = vi + a * t
vf = a * t
rearranging for a
a = vf / t (1)
now with the position equation we know that:
x = vi * t + (a * t ^ 2) / 2
x = (a * t ^ 2) / 2 (2)
now replacing (1) in (2), we are left with:
x = (vf / t) * (t ^ 2) / 2
knowing that x would be 2.33 ft, which is when the cannonball exits the cannon.
2.33 = 2700 * t / 2
t = 2.33 * 2/2700 = 0.001725 seconds.
and now replace in (1)
a = vf / t = 2700 / 0.001725 = 1565217.39 ft / s ^ 2
The answer to the question should be option B
Twenty-five times two = fifty
Answer:
use a2+b2=c2 so
Step-by-step explanation:
11(squared)+b(squared)=13(squared)
=121+b2=169
-121. -121
b2= 48
square root 48
Side B= 6.928
and then just round 6.928
hope this helped
Answer:
D
Step-by-step explanation:
Graph D has a positive slope. The line goes <em>up 2 units and right 3 units.</em>
