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3 years ago

You invest 1300 in a account that pays an interest rate of 4.75% what's the balance after 5 years ?

1 answer:

4 0

Total = Principal * (1 + rate)^years
Total = 1,300 * (1.0475) ^ 5
Total = 1,300 * 1.2611599139 
Total = 1,639.51

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A humanities professor assigns letter grades on a test according to the following scheme. A: Top 12% of scores B: Scores below t

RUDIKE [14]

Answer:

The minimum score required for an A grade is 88.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 77.8, \sigma = 8.5$

Find the minimum score required for an A grade.

Top 12%, which is at least the 100-12 = 88th percentile, which is the value of X when Z has a pvalue of 0.88. So it is X when Z = 1.175.

$Z = \frac{X - \mu}{\sigma}$

$1.175 = \frac{X - 77.8}{8.5}$

$X - 77.8 = 1.175*8.5$

$X = 87.8$

Rounding to the nearest whole number

The minimum score required for an A grade is 88.

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3 years ago

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Write the slope intercept form of the equation of the line through the given points x intercept of -5 and y intercept of -1. Pls

soldier1979 [14.2K]

bearing in mind that an x-intercept is when the graph touches the x-axis and when that happens y = 0, and a y-intercept is when the graph touches the y-axis and when that happens x = 0.

$\bf \underset{x-intercept}{(\stackrel{x_1}{-5}~,~\stackrel{y_1}{0})}\qquad \underset{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{-1}{0+5}\implies -\cfrac{1}{5}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{1}{5}}[x-\stackrel{x_1}{(-5)}] \\\\\\ y=-\cfrac{1}{5}(x+5)\implies y = -\cfrac{1}{5}x-1$

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3 years ago

Shawn is collecting money from students at his school for charity the table gives the ratio of the number of students who have d

Mama L [17]

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3 years ago

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If f is differentiable at x = c, then f is continuous at x = c. True False

TiliK225 [7]

The answer is false!!!

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3 years ago

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The headlights of an automobile are set such that the beam drops 3 in for each 32 ft in front of the car. What is the angle (giv

Anastaziya [24]

Answer:

0.4476 degrees.

Step-by-step explanation:

Let θ be the angle between the beam and the road. The given values form a right triangle with the distance that the beam drops ( h=3 in) being the side opposite to θ and the distance in front of the car (x=32 ft or x=384 in) being the side adjacent to θ.

Therefore, θ is given by:

$tan^{-1}(\theta) = \frac{h}{x}\\tan^{-1}(\theta) = \frac{3}{384}\\ tan^{-1}(\theta) = \frac{1}{128}\\\theta=0.4476^o$

The angle between the beam and the road is 0.4476 degrees.

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3 years ago