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3 years ago

How is (or how can you make) y/(1-x) equal to (1+x)/y

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

I hope this helps you

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Question in attachment

maxonik [38]

Solution:

When, you rotate a picture by 180°, we rotate it by half of a full circle.
The first picture is the original picture.
The second picture is the image when it is rotated by 90°.
The third picture is the images when, it is rotated once more by 90°. This image is the rotation of the image around P by 180°.
So, the answer will be option A.

Answer:

Option A.

Hope you could understand.

If you have any query, feel free to ask.

8 0

2 years ago

Simplify. Final answers should be written in standard form. (Reminder: in order to indicate an exponent you must use the carrot

rosijanka [135]

Answer:

-12w^3+32w^2-136w+80

Step-by-step explanation:

4(2-3w)(w^2-2w+10)

multiply first two:

(8-12w)(w^2-2w+10)

multiply:

8w^2-16w+80-12w^3+24w^2-120w

simplify:

-12w^3+32w^2-136w+80

7 0

3 years ago

How many sequences of length 5 can be made when each component of the sequence can take 3 different values?

kozerog [31]

Each position in the sequence has 3 choices, and there are 5 positions, so we multiply 3 by itself 5 times:

$3^5=243$

4 0

4 years ago

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago

Select f(x) = 1/(1 - x).

Arte-miy333 [17]

Duck iimwisis is the time is the last day to a week or two or three days of February and February

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4 years ago