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AfilCa [17]
3 years ago
9

What is (4-10)(4-2)divided by 12+2

Mathematics
2 answers:
pshichka [43]3 years ago
6 0
(-6)times 2/ 12/2
(-6) times 1/12
-.5 is the correct answer 
Sergeeva-Olga [200]3 years ago
5 0
So (4-10)(4-2) is -12 and -12 divided by 12 is <span>-0.85714285714 rounded to nearest hundredth its -0.86</span>
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An aquarium tank can hold 6300 liters of water. There are two pipes that can be used to fill the tank.The first pipe alone can f
liq [111]

Answer: it will take them 28 minutes to fill the tank.

Step-by-step explanation:

The first pipe alone can fill the tank in 84 minutes. This means that the rate at which the first pipe fills the tank per minute is 1/84

The second pipe can fill the tank in 42 minutes by itself. This means that the rate at which the second pipe fills the tank per minute is 1/42

If they work together, they would work simultaneously and their individual rates are additive. This means that their combined rate of filling the tank would be

1/84 + 1/42

Assuming it takes t hours for both pipes to fill the tank working together, the working rate per minute would be 1/t. Therefore,

1/84 + 1/42 = 1/t

3/84 = 1/t

t = 84/3

t = 28 minutes

6 0
4 years ago
Read 2 more answers
I need help please my marking period end tomorrow
yarga [219]
Number 5 should be no solution becuase the n's cancel out.

For 6:
Part A is -2 because slope represents the change in weigh/change in time (-2/1 or -2)
Part B is y=-2x+231 (-2 is the slope and 231 is the y-intercept)
For part C, based on the slope, we can find that her weight will go below 200 at week 16 when it is 199

Hope this helps!
6 0
4 years ago
Which ordered pair is a solution of x-y=2 and <br> 3y-x=8
Leokris [45]

The ordered pair is a solution of x - y = 2 and  3y - x = 8 is (x, y) = (7, 5)

<h3><u>Solution:</u></h3>

Given two equations are:

x - y = 2 and 3y - x = 8

<em><u>To find: orderes pair i.e (x, y)</u></em>

Let us consider:

x - y = 2 ------- eqn 1

3y - x = 8 --------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "x" and "y"</u></em>

On rearranging eqn 2, we get

-x + 3y = 8 ------ eqn 3

Add eqn 1 and eqn 3

x - y = 2

-x + 3y = 8

(+) ---------------

0 + 2y = 10

2y = 10

<h3>y = 5</h3>

Therefore from eqn 1,

x - y = 2

x - 5 = 2

x = 5 + 2 = 7

<h3>x = 7</h3>

Thus the ordered pair to the given equations are (x, y) = (7, 5)

8 0
3 years ago
Question 1
Arada [10]
The answer is n+7 and 7+n
5 0
3 years ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
4 years ago
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