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san4es73 [151]
3 years ago
9

Help please 15 points up for grabs

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

a) P(3) = \frac{11}{100} (or 0.11 or 11%)

b) Number of sixes = P(6) x 500

                                = \frac{12}{100} x 500

                                = 12 x 5

                                = 60

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square root 162

Step-by-step explanation:

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2 years ago
What is the quadratic portion in this quadratic equation 7x2-12x+16=0
alexdok [17]

Answer:

x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

Step-by-step explanation:

Solve for x:

7 x^2 - 12 x + 16 = 0

Hint: | Write the quadratic equation in standard form.

Divide both sides by 7:

x^2 - (12 x)/7 + 16/7 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 16/7 from both sides:

x^2 - (12 x)/7 = -16/7

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 36/49 to both sides:

x^2 - (12 x)/7 + 36/49 = -76/49

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 6/7)^2 = -76/49

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 6/7 = (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the first equation: Solve for x.

Add 6/7 to both sides:

x = 6/7 + (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the second equation: Solve for x.

Add 6/7 to both sides:

Answer:  x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

6 0
3 years ago
The legend on a map reads 1.25 inches represents 500 miles. If the measurement on the map between two locations is 3 inches, how
ser-zykov [4K]

Answer:

These two locations are 1200 miles apart.

Step-by-step explanation:

This question is solved using proportions, by a rule of three.

We have that:

1.25 inches represents 500 miles. 3 inches will represent x miles. So

1.25 inches - 500 miles

3 inches - x miles

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1.25x = 500*3

1.25x = 1500

x = \frac{1500}{1.25}

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These two locations are 1200 miles apart.

6 0
3 years ago
Wendy is standing 60 feet away from a tree. Her eyes are 5 feet above the ground. She sees a bird hovering above a tree. The ang
andreev551 [17]

Answer:

a) The tree is 32.98 feet  tall.

b) The bird is 50.21 feet high in the air.

c) The Bird is 17.23 feet far above the Tree.

Step-by-step explanation:

From the attached diagram, please familiarize yourself with the statement drawn out and the points drawn out for better understanding.

Note that Line CD is the ground level and Line QE is the Wendy's eyes height.

1) <em>How tall is the tree</em> (Line BC)

line BC (tree height) => QC + QB

Line ED = QC,  ∴ QC = <em>5 ft</em>

Since <BEQ = 25° and CD = QE, ∴ QE = 60ft all in triangle BEQ

Therefore Tan 25° = BQ/60

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BQ = <em>27.98 ft</em>

tree height => QC + QB = 5 ft + 27.98 ft ==> 32.98 ft

2) <em>How high is the bird in the air?</em> (Line AC)

line AC (bird height) => QC + QA

Line ED = QC,  ∴ QC = <em>5 ft</em>

Since <AEQ = 37° and CD = QE, ∴ QE = 60ft in triangle AEQ

Therefore Tan 37° = QA/60

QA = 60 (0.7536)

QA = <em>45.21 ft</em>

bird height => QC + QA = 5 ft + 45.21 ft ==> 50.21 ft

3) <em>How far above the tree is the bird?</em>

The difference between the bird height and the tree height = Line AC - Line BC

= 50.21 ft - 32.98 ft

= 17.23 ft

8 0
3 years ago
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