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Nikolay [14]
3 years ago
13

Timmy's reading a book on Monday evening 3 pages on that day on each day after that he read thre

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0
12 pages on thursday
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Which is the average rate of change over the interval [0, 10]? Hint: Find rate of change for both equations
GaryK [48]
Bzndjdjdjjdjdkdjkdkd
8 0
2 years ago
Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).​
Reil [10]

Answer:

Part A) sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}

Part B) tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}

Part C) sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}

Step-by-step explanation:

Part A) Find sin(\alpha)\ and\ cos(\beta)

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sin(\alpha)=cos(\beta)

Find the value of sin(\alpha) in the right triangle of the figure

sin(\alpha)=\frac{8}{14} ---> opposite side divided by the hypotenuse

simplify

sin(\alpha)=\frac{4}{7}

therefore

sin(\alpha)=\frac{4}{7}

cos(\beta)=\frac{4}{7}

Part B) Find tan(\alpha)\ and\ cot(\beta)

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

tan(\alpha)=cot(\beta)

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132

x=\sqrt{132}\ units

simplify

x=2\sqrt{33}\ units

Find the value of tan(\alpha) in the right triangle of the figure

tan(\alpha)=\frac{8}{2\sqrt{33}} ---> opposite side divided by the adjacent side angle alpha

simplify

tan(\alpha)=\frac{4}{\sqrt{33}}

therefore

tan(\alpha)=\frac{4}{\sqrt{33}}

tan(\beta)=\frac{4}{\sqrt{33}}

Part C) Find sec(\alpha)\ and\ csc(\beta)

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

sec(\alpha)=csc(\beta)

Find the value of sec(\alpha) in the right triangle of the figure

sec(\alpha)=\frac{1}{cos(\alpha)}

Find the value of cos(\alpha)

cos(\alpha)=\frac{2\sqrt{33}}{14} ---> adjacent side divided by the hypotenuse

simplify

cos(\alpha)=\frac{\sqrt{33}}{7}

therefore

sec(\alpha)=\frac{7}{\sqrt{33}}

csc(\beta)=\frac{7}{\sqrt{33}}

6 0
3 years ago
Stella bought 14 purses for $50. The next day she bought 2 more for a total of $38. What was the mean cost per purse?
denpristay [2]

Answer:

$48.5

Step-by-step explanation:

Given data

Number of purses= 14+2= 16

Cost of 14 purses= $50

Cost of 2 purses= $38

Let us use the weighted cost method

Mean cost = (14*50+ 2*38)/16

Mean cost = (700+ 76)/16

Mean cost = 776/16

Mean cost =$48.5

8 0
3 years ago
Find the median and mode of the following data:
jekas [21]
A is 4 and b is 63 have a good day
4 0
2 years ago
Read 2 more answers
Please help ASAP<br> f(x)=2-3x<br> Evaluate f(4)
natima [27]
F(4) is 10 all you do is plug in 4 for x
6 0
3 years ago
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