
As we know ~
Area of the circle is :

And radius (r) = diameter (d) ÷ 2
[ radius of the circle = half the measure of diameter ]
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<h3>Problem 1</h3>



Now find the Area ~




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<h3>problem 2</h3>



Bow, calculate the Area ~




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<h3>Problem 3 </h3>




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<h3>Problem 4</h3>



now, let's calculate area ~



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<h3>problem 5</h3>



Now, let's calculate area ~




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<h3>problem 6</h3>




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Answer:
3d + 1
I'm pretty sure it's the same thing.
If you need further help on how they got the answer, this equation will take more time, but it will also help you understand these types of problems. Part÷Whole=Percent÷100
Part= X because it is what you are trying to find.
Whole=250 because it is what you are taking the percentage of.
Percent=80
Now you have:
X÷250=80÷100
Set this up in fraction form and cross multiply.
You get:
100x=250×80
250×80=20,000
100x=20,000
X=200
Answer:
There are 40 problems on the test
Step-by-step explanation:
Let p = the number of problems on the test
The number of problems on the test times the percent correct is the number correct
p * 85% = 34
p * .85 = 34
Divide each side by .85
p * .85/.85 = 34/.85
p = 40
There are 40 problems on the test
2) -6
8 is positive and 14 negative. You can either draw a number line and help yourself with that or since the negative one is bigger you can do the subtraction 14 - 8 and then change the sign of the answer.