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Anestetic [448]
3 years ago
8

Aubrey is 2 years less than three times Jim's age. If Aubrey is 13 how old is Jim?

Mathematics
2 answers:
34kurt3 years ago
7 0

first you need to mulitply 13 x 3 which is 39, then subtract 2 which is 37.

myrzilka [38]3 years ago
4 0

This is how I interpret the question.

13 x 3 -2 = 37

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How do I do this ? I don’t understand logarithm
ale4655 [162]

Hello from MrBillDoesMath!

Answer:

x = 19

Discussion:

Both sides are logarithms to the same base, namely 20 , which implies the expressions in x (what we are taking logarithms of) must be equal. So we need to solve

4x - 10 = 3x + 9              => subtract 3x from both sides

4x-3x - 10 = 9                 => add 10 to both sides

x = 9 + 10 = 19

Thank you,

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3 years ago
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Sati [7]

Answer:

Rectangle C is not similar to the other 2

Step-by-step explanation:

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3 years ago
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The perimeter of a semicircle is 5.14 feet. What is the semicircle’s area?
hammer [34]
\bf \textit{circumference of a semi-circle}\\\\
C=\pi r\qquad 
\begin{cases}
r=radius\\
-----\\
C=5.14
\end{cases}\implies 5.14=\pi r\implies \boxed{\cfrac{5.14}{\pi }=r}\\\\
-------------------------------\\\\
\textit{area of a semi-circle}\\\\
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5 0
3 years ago
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Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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