Write this sentence as an equation. 246 is equal to w reduced by 257

Mathematics

1 answer:

blondinia [14]3 years ago

8 0

Answer: 246 = w - 257

Step-by-step explanation:

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Use the function below to find f(3) ........ F(x)=1/3•4^x

tankabanditka [31]

Answer:

$21\frac{1}{3}$

Step-by-step explanation:

F(x)=1/3•4^x

f(3) = 1/3•4^3 = 64 / 3 = $21\frac{1}{3}$

5 0

3 years ago

Which of these is NOT an integer

Tema [17]

Hi there!

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I believe your answer is:

Option A

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Here’s why:

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$\boxed{\text{Option A:}}\\\\3^{-5}\\\\\rightarrow \frac{1}{3^5}\\\\\rightarrow \frac{1}{243}\\\\\ \text{This is \textbf{NOT} an integer.}}$

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$\boxed{\text{Option B:}}\\\\-3^5\\\\\rightarrow -3 * -3 * -3 * -3 * -3 \\\\\rightarrow \boxed{-243}\\\\\\\text{This \textbf{IS} an integer.}$

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$\boxed{\text{Option C:}}\\\\\frac{1}{3}^{-5} \\\\\rightarrow \frac{1}{(\frac{1}{3})^5}\\\\\rightarrow \frac{1}{\frac{1}{243} }\\\\\rightarrow \boxed{243}\\\\\\\text{This \textbf{IS} an integer.}$

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$\text{Option \textbf{A} does not simplify into an integer.}$

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Hope this helps you. I apologize if it’s incorrect.

7 0

3 years ago

G prove that limx→∞(x 2 + 1)/x2 = 1 using the definition of limit at ∞.

Maslowich

$\displaystyle\lim_{x\to\infty}\frac{x^2+1}{x^2}=1$

means to say there is some number $M$ for which any choice of $\varepsilon>0$ such that

$x>M\implies\left|\dfrac{x^2+1}{x^2}-1\right|$

Working backwards, we have

$\left|\dfrac{x^2+1}{x^2}-1\right|=\left|1+\dfrac1{x^2}-1\right|=\dfrac1{x^2}$
$\implies\sqrt{\dfrac1{x^2}}$

So, whenever $x>M=\dfrac1{\sqrt\varepsilon}$ , we can always guarantee that $\left|\dfrac{x^2+1}{x^2}-1\right|$ .