1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
evablogger [386]
3 years ago
9

To some Marines one cruising at 25 kn in the other 20 kn left the naval base at the same moment. Three hours later they were 100

nautical miles apart. What is the measure between their horses ?
Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0
I believe you would have to multiply both 25 and 20 and what ever number you get dived by 100 if the numbers to high multiply aging or subtract the number (if it's wrong I'm really not good at my math I'm sorry)
You might be interested in
Please help me ! I don’t know !
goblinko [34]

Answer:

5

Step-by-step explanation:

this will endure the bitextular number course and follow the index pattern once you do that follow the question to get 5

7 0
3 years ago
Read 2 more answers
Find the angle between the hands of a clock at 5:15<br><br> A 60<br> B 67.5<br> C 75
Viktor [21]

Answer:

Option B is correct.

67.5 degree

Step-by-step explanation:

To find the angle between the hands of a clock.

Given that:

Hands of a clock at 5 : 15.

We know that:

A clock is a circle and it always contains 360 degree.

Since, there are 60 minutes on a clock.

\frac{360^{\circ}}{60 minutes} = 6^{\circ} per minutes

so,  each minute is 6 degree.

The minutes hand on the clock will point at 15 minute,

then, its position on the clock is:

(15) \cdot 6^{\circ} = 90^{\circ}

Also, there are 12 hours on the clock

⇒Each hour is 30 degree.

Now, can calculate where the hour hand at 5:00 clock.

⇒5 \cdot 30 =150^{\circ}

Since, the hours hand is between 5 and 6 and we are looking for 5:15 then :

15 minutes is equal to \frac{1}{4} of an hour

⇒150+\frac{1}{4}(30) = 150+7.5 = 157.5^{\circ}

Then the angle between two hands of clock:

⇒\theta = 150.75 -90 = 67.5^{\circ}

Therefore, the angle between the hands of a clock at 5: 15 is: 67.5 degree.

4 0
3 years ago
Read 2 more answers
Rewrite the conditional statement in if-then form: 3x + 2 = 23, because x = 7
Flauer [41]

Answer:3(7)+2=23. 21+2=23

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What are the factors of 14 and the prime number
Dafna11 [192]
The factors of 14 are 1,2,7, and 14. The prime number are 2 and 7.
3 0
3 years ago
Read 2 more answers
The sum of two numbers is 52. One number is 3 times as large as the other number. Which is the larger number
creativ13 [48]

The two number are 39 and 13

<em><u>Solution:</u></em>

Let the two numbers be "a" and "b"

Let the larger number be "a" and the smaller number be "b"

<em><u>Given that, sum of two numbers is 52</u></em>

a + b = 52 ---------- eqn 1

<em><u>One number is 3 times as large as the other number</u></em>

Larger number = 3 times smaller number

a = 3b -------- eqn 2

<em><u>Let us solve eqn 1and eqn 2</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

3b + b = 52

4b = 52

b = 13

<em><u>Substitute b = 13 in eqn 2</u></em>

a = 3(13)

a = 39

Thus the two number are 39 and 13

4 0
3 years ago
Other questions:
  • Can someone help me with at least one of the problems I’m stuck on? Thank you!
    6·1 answer
  • Please help ASAP ill appreciate it a lot
    10·1 answer
  • Please help thank you
    10·2 answers
  • Can someone help me with 4 and 5 please
    15·1 answer
  • Maria, Ahmad, and Bob sent a total of 52 text messages during the weekend. Maria sent fewer messages than Bob. Ahmad sent times
    9·1 answer
  • Which expressions are equivalent to z0.2?
    10·1 answer
  • Jerome purchased a 4-year old car for $12,000. He was told this make a model depreciates exponentially at a rate of 5.7% each ye
    13·1 answer
  • Math- find the angle OPR.
    8·2 answers
  • Ill give a brainliest
    14·2 answers
  • For the limit
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!