To some Marines one cruising at 25 kn in the other 20 kn left the naval base at the same moment. Three hours later they were 100
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Y = mx + b
Therefore we have: y = 3x + b.
Put the coordinates of the point (3; 2) to the equation of the line:
Therefore we have: y = 3x - 7
Substitute the coordinates of the point (8; y) to the equation of the line:
Answer: y = 17.
Therefore we have: y = 3x + b.
Put the coordinates of the point (3; 2) to the equation of the line:
Therefore we have: y = 3x - 7
Substitute the coordinates of the point (8; y) to the equation of the line:
Answer: y = 17.