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3 years ago

Can someone help me with this question please

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

The answer is A because it has the lowest price per ounce.

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Martha earned $180 during the summer doing chores. She bought 3 books worth $14 each using her chore money. How much money was l

Viktor [21]

Answer:

$138

Step-by-step explanation:

We can first turn the words into a mathematical equation by substituting words with the information we have:

Total earning - ( Price of three books)

$180 - (Price of one book x 3)

$180 - ($14 x 3)

Finally, after we have created the mathematical equation, we solve it!

$180 - ($14 x 3)

$180 - $42

$138

6 0

3 years ago

The sum of the first 20 positive odd integers

svet-max [94.6K]

Answer:

$400$

Step-by-step explanation:

$We\ know\ that,\\'The\ sum\ of\ n\ no.\ positive\ odd\ integers\ is\ given\ by\ the\ formula:\\S_O=n^2\\Hence,\\Here,\\As\ n=20,\\The\ sum\ of\ the\ first\ 20\ positive\ odd\ integers=20^2=400\\$

7 0

3 years ago

A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th

umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable X is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, p = 0.09.

An item is defective irrespective of the others.

The random variable X follows a Binomial distribution with parameters n = 9 and p = 0.09.

The repair cost of the item is given by:

$C=3X^{2}+X+2$

Compute the expected cost of repair as follows:

$E(C)=E(3X^{2}+X+2)$

$=3E(X^{2})+E(X)+2$

Compute the expected value of X as follows:

$E(X)=np$

$=4\times 0.09\\=0.36$

The expected value of X is 0.36.

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=4\times 0.09\times 0.91\\=0.3276\\$

The variance of X is 0.3276.

The variance can also be computed using the formula:

$V(X)=E(Y^{2})-(E(Y))^{2}$

Then the formula of $E(Y^{2})$ is:

$E(Y^{2})=V(X)+(E(Y))^{2}$

Compute the value of $E(Y^{2})$ as follows:

$E(Y^{2})=V(X)+(E(Y))^{2}$

$=0.3276+(0.36)^{2}\\=0.4572$

The expected repair cost is:

$E(C)=3E(X^{2})+E(X)+2$

$=(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73$

Thus, the expected repair cost is $3.73.

4 0

3 years ago

Can you please help me with this urgently need help? It is grade 12 advance function question

andrey2020 [161]

Answer: The spin of the wheel by the contestant is an illustration of a sine function whose equation is y = -1.25sin(0.8x + 0.25)

8 0

2 years ago

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Find the retail price of a new laptop. Original cost: $899.99; Markup 7%

KATRIN_1 [288]

Original cost: $899.99
Markup (7%): 0.07($899.99)
Retail price = original cost plus markup = 1.07($899.99) = $962.99 (answer)

8 0

3 years ago

Read 2 more answers