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lianna [129]
3 years ago
12

If f (x) = x + 7 and g (x) = StartFraction 1 Over x minus 13 EndFraction, what is the domain of (f circle g) (x)?

Mathematics
2 answers:
Rashid [163]3 years ago
6 0

Answer:

R-{13}

Step-by-step explanation:

We are given that

f(x)=x+7

g(x)=\frac{1}{x-13}

We have to find the domain of fog(x).

fog(x)=f(g(x))

fog(x)=f(\frac{1}{x-13})

fog(x)=\frac{1}{x-13}+7=\frac{1+7x-91}{x-13}=\frac{7x-90}{x-13}

Domain of f(x)=R

Because it is linear function.

Domain of g(x)=R-{13}

Because the g(x) is not defined at x=13

fog(x) is not defined at x=13

Therefore, domain of fog(x)=R-{13}

LenaWriter [7]3 years ago
3 0

Answer:

The domain is all real values of  except x = 13.

Step-by-step explanation:

(f o g)(x) =  (1/ (x - 13))  + 7.

The domain is all real numbers except x = 13.

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galina1969 [7]

Answer:

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Step-by-step explanation:

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3 years ago
Camila sets up a passcode on her tablet, which allows only nine-digit codes. A spy sneaks a look at Camila's tablet and sees her
laila [671]

Answer:

\frac{1}{10^9} probability the spy is able to unlock the tablet on his first try.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

1 correct password, so D = 1

Total outcomes:

Nine-digit codes.

For each digit, there are 10 possible outcomes. So

T = 10^9

What is the probability the spy is able to unlock the tablet on his first try?

p = \frac{D}{T} = \frac{1}{10^9}

\frac{1}{10^9} probability the spy is able to unlock the tablet on his first try.

7 0
3 years ago
May someone help me on this please
grigory [225]
Sure! It's 0.01 liters
7 0
3 years ago
Instructions:Select the correct answer. Dexter's dad runs a toy store. His current yearly sales report shows that he sold 4,694
grigory [225]
The store made 13,847.30 dollars
7 0
3 years ago
Read 2 more answers
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
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