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Rus_ich [418]
3 years ago
13

What is orbitals in the chemistry definition

Chemistry
2 answers:
Nataly_w [17]3 years ago
5 0

Orbitals or otherwise fully known as <u>Atomic orbitals</u> are regions of space around the nucleus of an atom. This is also where an electron believed to be found.  The atomic orbitals allow atoms to make covalent bonds.

Hope I could help! :)

professor190 [17]3 years ago
4 0

Good afternoon!

An orbital, in chemistry, can be described as a layer where an electron is expected to be found, around a nucleus of an atom.

Atoms contain 3 parts - protons, neutrons, and electrons. The protons and neutrons stick together in the center, while the electrons are flying around the entire nucleus (protons+neutrons).

The location of these electrons is unknown, as they fly around, however there is a "most likely found" location.

These are the orbitals. They are the areas where the electron is most likely to be found.

Good luck!

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Many power plants produce energy by burning carbon-based fuels, which also produces carbon dioxide. Carbon dioxide is a greenhou
RUDIKE [14]

Answer:

a) 2.541 mol/MJ;

b) 1.124 mol/MJ;

c) 0.4354 mol/MJ;

d) 0.1835 mol/MJ

Explanation:

The enthalpy of formation (ΔH°f) is the enthalpy of a reaction to form a compound by its constituents. For CO₂, ΔH°f = - 393.5 kJ/mol.

The enthalpy of a reaction is the sum of the enthalpy of the products (each one multiplied by the number of moles) less the sum of the enthalpy of the reactants (each one multiplied by the number of moles). The ΔH°f for simple substances (with one atom) is 0. The combustion is the reaction between the fuel and the oxygen.

a) The combution reaction is:

C(s) + O₂(g) → CO₂(g)

ΔH°rxn = -393.5 kJ/mol = -393.5x10⁻³ MJ/mol

Number of moles per MJ released: 1/|ΔH°rxn|

n = 1/(393.5x10⁻³) = 2.541 mol/MJ

b) The combustion reaction is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

H₂O is in the liquid state because it's at 1 atm and 25ºC.

ΔH°f, H₂O(l) = -285.3 kJ/mol

ΔH°f, O₂(g) = 0

ΔH°f, CH₄(g) = -74.8 kJ/mol

ΔH°rxn = [2*(-285.3 ) + 1*(-393.5)] - [1*(-74.8)]

ΔH°rxn = -889.3 kJ/mol = -889.3x10⁻³ MJ/mol

n = 1/889.3x10⁻³ = 1.124 mol/MJ

c) C₃H₈(g) + 10O₂(g) → 3CO₂(g) + 4H₂O(l)

ΔH°f,C₃H₈(g) = -25.2 kJ/mol

ΔH°rxn = [4*(-285.3) + 3*(-393.5)] - [1*(-25.2)]

ΔH°rxn = -2,296.5 kJ/mol = -2.2965 MJ/mol

n = 1/2.2965 = 0.4354 mol/MJ

d) C₈H₁₈(l) + (25/2)O₂(g) → 8CO₂(g) + 9H₂O(l)

ΔH°f, C₈H₁₈(l) = -250.1 kJ/mol

ΔH°rxn = [9*(-283.5) + 8*(-393.5)] - [1*(-250.1)]

ΔH°rxn = -5,449.4 kJ/mol = -5.4494 MJ/mol

n = 1/5.4494 = 0.1835 mol/MJ

4 0
3 years ago
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frozen [14]
First write all of the compounds/atoms in either side then fill in existing values and balance


Na- 1
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Na- 1
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7 0
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LenaWriter [7]

Answer:

D. The relationship between volume and moles

Explanation:

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The law states that "equal volume of all gases at the same temperature and pressure contains the same number of molecules or moles".

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                         V ∝ n (P,T constant)

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